Posted by **jude** on Saturday, February 6, 2010 at 2:20am.

Given a square of sidelength a = 5 cm. We place a charged particle at each corner, three of them carry + 2 nC of charge and one carries the same amount of negative charge.

What is the magnitude of the electric field at the center of the square?

I dont know how to start this problem and would really appreciate it if someone could tell me the method.

Thank you

- physics -
**drwls**, Saturday, February 6, 2010 at 2:27am
The center of the square is 5/sqrt2 = 3.535 cm from each corner. The fields due to the two +2nC charges at opposite corners will cancel out. The other two opposite charges will add, and the field will act along the diagonal between them.

Calculate the E field due to the negative charge using Coulomb's Law, and double it to account for the positive charge at the opposite corner.

- physics -
**Sandra**, Saturday, February 6, 2010 at 2:25pm
Is the point charge considered to have a charge of 1?

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