Posted by adam on .
A 28 kg chair intially at rest on a horizontal floor requires a 360 N horizontal force to set it in motion. Once the chair is in motion, a 329 N horizontail force keeps moving it at a constant velocity. The acceleration of gravity is 9.81 m/s^2. What is the coefficient of static friction between the chair and floor?
Why have you listed the subject as "Cleveland"?
The static friction coefficient is the force reuired to start it moving, divided by M g.
The kinetic friction coefficient is the force required to keep it moving at constant speed, divided by M g.
M g in this case is 28 x 9.81 Newtons