Posted by Meg on Tuesday, December 8, 2009 at 6:36pm.
If KrF2 is linear and symmetric, it is not a dipole. The others probably are. a molecule needs symmetry about a plane to avoid being a dipole. You can't always tell that from the chemical formula.
CH2Br2 is a molecule
Br-CH2-Br, linear almost, no dipole
SCN-
::S=C=N: triple bond between C,N
most definitely has dipole moment
I take the CH2Br2 back. It is a bent tetrahedral, so the Br side gives it a dipole moment.
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