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July 30, 2015

July 30, 2015

Posted by **Shannon** on Sunday, December 6, 2009 at 5:07am.

I believe the substitution method is the proper way?

- calculus -
**drwls**, Sunday, December 6, 2009 at 8:25amYes, substituion will work.

Let x+1 = u

x = (u-1)

dx = du

S x*(x+1)^9 dx = S (u-1)u^9 du

= S u^10 du - S u^9 du

= (u^11)/11 - (u^10)/10

= [(x+1)^11]/11 - [(x+1)^10]/10