Post a New Question

Precalculus

posted by on .

Sorry ok I was talking about on the unit circle how come the slope of the reference line (say if you were to angle pi/2, the reference line would be the positive y axis from y equals zero to y equals one, I think this line is called this, like if you were to draw pi/4 on the unit circle you would indicate this by drawing a line that is not on the circle arleady... this line is the line I'm referencing) how come the slope of this line or the first deriviative of it is equal to tangent

tan theta = (dsine(theta))/(dcos(theta))

???

  • Precalculus - ,

    tangent theta is equal to

    the derivative of sine theta
    over
    the derivative of cosine theta?

  • Precalculus - ,

    I think you are greatly confused.

    The slope of any line at an angle theta from the reference line is equal to tangent theta.

    tangenttheta is NOT equal to derivative of sin over the derivative of cosine.

    Why is slope equal to tangent?

    slope is defined as deltaY/deltax where x is the reference point for the angle. but deltaY/deltaX is by definition the tangent of the central angle, theta.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question