Post a New Question

Algebra 1

posted by on .

Marcus and Allen are playing Rock/Paper/Scissors. The first one to one 10 times does not have to do the dishes. The score is now 9 to 7 in favor of Marcus. If ties are ignored and not counted, what is the probabilty Marcus will not have to do the dishes? Express your answer as a common fraction.

  • Algebra 1 - ,

    Ad the following probabilities (ties not counted):
    Marcus wins next
    Marcus loses and then wins second decision
    Marcus loses twice and then wins third decision.
    1/2 + 1/2^2 + 1/2^3
    = (12 + 6 + 3)/24
    = 7/8

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question