Posted by Emily on Tuesday, November 3, 2009 at 8:42pm.
This question was answered one or two days ago
Let it have v as a final velocity
Then, w=v/r at the bottom
Ke= 1/2 mv^2+ 1/2Iw^2
but KE= mgh=mg*334Sin22.4
so..
mg*334sin22.4=1/2mv^2+ I v^2/r^2
Now we need to work on v...
The averagevelocity was v/2=distance/time
v= 2*3.34/1.89sec
Put that into
mg*334sin22.4=1/2mv^2+ I v^2/r^2
and solve for momentof inertial.
check my thinking.
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