Posted by Laura on Wednesday, October 28, 2009 at 3:19pm.
LS
= [(cscx - cotx)(cscx + cotx)]^4
= [csc^2x - cot^2x]^4
= [1 + cot^2x - cot^2x]^4
= [1]^4
= 1
= RS
Related Questions
trig - express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is ...
drwls - My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an ...
trig - Prove (cscx+cotx)(cscx-cotx)=1
Math - prove:(cscx-cotx)^4 x (cscx+cotx)^4 = 1
calculus - express in sinx 1 1 ---------- + -------- cscx + cotx cscx - cotx and...
Precalculus - Simplify:[(cscx-cotx)(cscx+cotx)]/cscx
Trig - prove (cscx-secx/cscx+secx)=(cotx-1/cotx+1)
ap calc bc - hi! ok, i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -...
Pre-Calculus - Find a numerical value of one trigonometric function of x if tanx...
Math - Im really struggling with these proving identities problems can somebody ...
For Further Reading
