Posted by **green** on Monday, October 26, 2009 at 4:02pm.

how can i write these equations in standard form with integer coefficients?

so #1 is: y=1/2x-3/5

and also #2: y=-8/3x+4/9

I know the formula is Ax+By=C..

but I just don't get these two..

plz explain & thanks!

- math -
**Reiny**, Monday, October 26, 2009 at 4:28pm
These require two steps.

1. clear the fractions by multiplying by the LCD

2. rearrange, so the x and y terms are on one side and the constant on the other, leading with a positive coefficient for x

1. multiply by 10

10y = 5x - 6

2. 6 = 5x - 10y or 5x - 10y = 6

Now you try the second in the same way.

- math -
**green**, Monday, October 26, 2009 at 4:54pm
so would number 2 be:

24x+9y=4 OR 4=24x+9y

??

thnx!

- math -
**Reiny**, Monday, October 26, 2009 at 5:04pm
Watch your signs

After you multiply by 9 you get

9y = 24x + 4

then 24x - 9y = -4 or -4 = 24x - 9y

the last two equations are the same thing.

(if A=B then B=A)

in the the general form, the x and y terms are "usually" on the left side of the equation, so 24x - 9y = -4 would be preferred.

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