Posted by **Devon** on Wednesday, October 14, 2009 at 5:21pm.

I'm trying to solve x^3-3x^2-x+3 is less than zero. Except, I'm not sure how to factor it. I tried splitting it so that 3 would be a factor for 3x^2 and 3, so the result was 3(-x^2+1), and x^2 was a factor for x^3 and -3x^2, resulting in x^2(x+3). But this will be really hard to find out the zeroes from. Can you explain a better way? Thanks!

## Answer This Question

## Related Questions

- maths - how do i solve this equation? there is another answer other than 0, but ...
- algebra - It is not solvable by that method, shanaid. You have to get all the ...
- algebra - The first three equations I have solved, I would just appreciate ...
- Algebra - The first three equations I have solved, I would just appreciate ...
- Algebra help - Solve Rational Inequalities x^2-x-2/x^2+5x+6<0 I cant figure ...
- algebra - 3ax^2 - 27a You can factor that into 3a (x^2 - 9), which also equals ...
- Algebra - Solve by factoring. n^2+n-12=0 I know i would need to factor it and ...
- Algebra 1 - The architect must factor several trinomials the are of the form x2...
- Algebra - I'm not sure how to factor 3x^3-12x^2+3x. I tried separatring the 3x ...
- Algebra - I was asked to use factoring and the zero-product property to solve ...

More Related Questions