Posted by Devon on .
I'm trying to solve x^33x^2x+3 is less than zero. Except, I'm not sure how to factor it. I tried splitting it so that 3 would be a factor for 3x^2 and 3, so the result was 3(x^2+1), and x^2 was a factor for x^3 and 3x^2, resulting in x^2(x+3). But this will be really hard to find out the zeroes from. Can you explain a better way? Thanks!

Algebra 
bobpursley,
x^33x^2x+3
x^2(x3)(x3)
(x3)(x^21)
(x3)(x+1)(x1)