SAC = STC/y = (w1(y/240)^2 + 48w2) / y
= (w1)(y/240)^2(y) + ((48)(w2))/y
= (w1)(y/240)^2 + ((48)(w2))/y <-- this is the final answer, but I don't understand it because of this part:
(w1)(y/240)^2(y) -> (w1)(y/240)^2
Don't you add exponents when you multiply variables? So wouldn't it become...
(w1)(y^3/240^2)??
Note: w1, y, w2 are variables
well, you can add, but remember this
1/y= y-1
(y^2/240^2)/y
(y^2/240^2)(y/1)
y^3/240^2???
I don't get how y^-1 is relevant to this question since (x/y)/z can be rearranged as (x/y)(z/1)..
In the given equation, SAC = (w1)(y/240)^2(y), it appears that there might be a confusion with the application of exponents.
Let's break it down step by step:
SAC = (w1)(y/240)^2(y)
First, we can simplify (y/240)^2 by squaring the fraction:
(y/240)^2 = (y^2/240^2)
Next, we can multiply this result by y:
(y^2/240^2)(y) = (y^3/240^2)
So, you are correct that the expression (w1)(y/240)^2(y) should simplify to (w1)(y^3/240^2).
However, in the final answer you provided, (w1)(y/240)^2 + ((48)(w2))/y, it seems that the expression (w1)(y/240)^2 has been separated from the rest of the equation ((48)(w2))/y.
To confirm, the final answer should be:
SAC = (w1)(y/240)^2 + ((48)(w2))/y
If you have any further questions or if there is something else you need assistance with, please let me know!