Wednesday

July 30, 2014

July 30, 2014

Posted by **Anonymous** on Wednesday, October 14, 2009 at 4:03pm.

= (w1)(y/240)^2(y) + ((48)(w2))/y

= (w1)(y/240)^2 + ((48)(w2))/y <-- this is the final answer, but I don't understand it because of this part:

(w1)(y/240)^2(y) -> (w1)(y/240)^2

Don't you add exponents when you multiply variables? So wouldn't it become...

(w1)(y^3/240^2)??

Note: w1, y, w2 are variables

- Exponent Rules -
**bobpursley**, Wednesday, October 14, 2009 at 4:27pmwell, you can add, but remember this

1/y= y^{-1}

- Exponent Rules -
**Anonymous**, Wednesday, October 14, 2009 at 4:32pm(y^2/240^2)/y

(y^2/240^2)(y/1)

y^3/240^2???

I don't get how y^-1 is relevant to this question since (x/y)/z can be rearranged as (x/y)(z/1)..

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