Posted by **Anonymous** on Wednesday, October 14, 2009 at 3:42pm.

Find d VC/ d y = ((y/240)^2)(w)

= 2yw/240^2 + 0 + y^2/240^2

but final answer is....

= 2yw/240^2

So, is the question asking for partial derivative or first derivative? I think partial because the final answer only took the derivative with respect to y.

- Is this f'(x) or partial derivative? -
**MathMate**, Wednesday, October 14, 2009 at 5:19pm
If VC(y)=((y/240)^2)(w)

then VC is not dependent on w, so if you differentiate as a product, the term containing dw/dy drops out (because dw/dy=0), giving you the correct answer.

If w is a function of y, namely w=w(y), then the term dw/dy should be kept:

d(VC)/dy = 2yw/240^2 + y^2/240^2*(dw/dy)

## Answer This Question

## Related Questions

- Exponent Rules - SAC = STC/y = (w1(y/240)^2 + 48w2) / y = (w1)(y/240)^2(y) + ((...
- Algebra - Which equation could be used to find the dimensions of a room that has...
- Algebra Repost - Which equation could be used to find the dimensions of a room ...
- Math - If 450 kilowatts of electric used cost 25.32, then how much would 240 ...
- Math ttriangles - how would I find the hieght of a isocscles triangle if the ...
- math - The question is a principal is choosing between field trips. The final ...
- trig - Use De Moivre's theorem to simplify the expression. Write the answer in ...
- algebra 1 - Ashley is the manager of a theater. She has $240 to spend on posters...
- math - For a tall kitchen bag the volume is set to be 240 in3. a. Write the ...
- Math - A motorist makes a journey of 240 km from Singapore to Malacca to visit ...

More Related Questions