Posted by Anonymous on Sunday, September 13, 2009 at 9:17pm.
let
u=initial velocity = 15 m/s
g=acceleration due to gravity = 9.8 m/s/s
S=-29 m
Using the equation
S=ut+(1/2)(-g)t²
the only unknown is the time t.
You will get two solutions, the negative one is when it was thrown from the street, and the other is the solution sought, and should be over 4 seconds.
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