Posted by Sarah on .
A bowling ball weighing 71.2 N is attached to the ceiling by a 3.80 m rope. The ball is pulled to one side and released; it then swings back and forth like a pedulum. as the rope swings through its lowest point, the speed of the bowling ball is measured at 4.20 m/s. At that instant, find a) the magnitude and direction of the acceleration of the bowling ball and b) the tension in the rope.

Physics 
drwls,
a) The magnitude of the acceleration is V^2/R and it is directed along the rope (i.e. vertical), perpendicular to the direction of motion.
b) If the rope tension is T, Newton's Second Law tells you that
F = T  Mg = Ma = M V^2/R
Solve for T
T = M*(g + V*2/R)
R is the rope length. 
Physics 
Sarah,
So for a I got 17.64 / 3.80 = 4.64 sec is this correct
and then for b i got 71.2( 9.8+ 4.20)*2 / 3.80 and got 524.63 
Physics 
Anonymous,
hell naw

Physics 
Anonymous,
LMBO!!!