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March 27, 2017

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A bowling ball weighing 71.2 N is attached to the ceiling by a 3.80 m rope. The ball is pulled to one side and released; it then swings back and forth like a pedulum. as the rope swings through its lowest point, the speed of the bowling ball is measured at 4.20 m/s. At that instant, find a) the magnitude and direction of the acceleration of the bowling ball and b) the tension in the rope.

  • Physics - ,

    a) The magnitude of the acceleration is V^2/R and it is directed along the rope (i.e. vertical), perpendicular to the direction of motion.

    b) If the rope tension is T, Newton's Second Law tells you that

    F = T - Mg = Ma = M V^2/R

    Solve for T

    T = M*(g + V*2/R)

    R is the rope length.

  • Physics - ,

    So for a I got 17.64 / 3.80 = 4.64 sec is this correct

    and then for b i got 71.2( 9.8+ 4.20)*2 / 3.80 and got 524.63

  • Physics - ,

    hell naw

  • Physics - ,

    LMBO!!!

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