Posted by Anonymous on Monday, May 11, 2009 at 3:00pm.
a) both local (2/5)*(2/5)
b) neither local both a Tads (3/5)*(3/5)*(5/6)*(5/6)
c) neither local neither a Tads (3/5)*(3/5)*(1/6)*(1/6)
d) one local, one at Tads 2*[(2/5)*(3/5)*(5/6)]
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