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February 1, 2015

February 1, 2015

Posted by **Becks** on Wednesday, April 29, 2009 at 9:33am.

2a-6(10a)-5a^2(2)

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(2a-6)^2

This is my work but its not right.

10a-10a^2

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2a-6

Then solve for a by setting numerator to zero. so I got this...

10a-10a^2=0

10a(1-a)=0

a=0, a=1

My book says a=0, or a=6 why didn't I get this?

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