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March 27, 2017

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How would I go about solving this equation algebraically?

Find the equation of the parabola

y=ax^2 + bx+c

that passes through the given points.

(2,0) (3,-1) (4,0)

Thanks.

  • Alg2/Trig - ,

    Sketch a graph.
    see that vertex is at (3.-1)
    so form is
    (y+1) = k(x-3)^2
    substitute in (2,0) to find k
    1 = k (-1)^2
    k = 1
    so
    y = (x-3)^2
    or
    y = x^2 - 6 x + 9

  • Alg2/Trig - ,

    I plugged that into my graphing calculator and that isn't right. Could someone help?

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