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December 20, 2014

December 20, 2014

Posted by **Chris** on Thursday, March 5, 2009 at 8:09pm.

Find the equation of the parabola

y=ax^2 + bx+c

that passes through the given points.

(2,0) (3,-1) (4,0)

Thanks.

- Alg2/Trig -
**Damon**, Thursday, March 5, 2009 at 9:00pmSketch a graph.

see that vertex is at (3.-1)

so form is

(y+1) = k(x-3)^2

substitute in (2,0) to find k

1 = k (-1)^2

k = 1

so

y = (x-3)^2

or

y = x^2 - 6 x + 9

- Alg2/Trig -
**Chris**, Friday, March 6, 2009 at 12:57amI plugged that into my graphing calculator and that isn't right. Could someone help?

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