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posted by Chris on Thursday, March 5, 2009 at 8:09pm.

How would I go about solving this equation algebraically? Find the equation of the parabola y=ax^2 + bx+c that passes through the given points. (2,0) (3,-1) (4,0) Thanks.

Sketch a graph. see that vertex is at (3.-1) so form is (y+1) = k(x-3)^2 substitute in (2,0) to find k 1 = k (-1)^2 k = 1 so y = (x-3)^2 or y = x^2 - 6 x + 9

I plugged that into my graphing calculator and that isn't right. Could someone help?

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