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February 28, 2015

February 28, 2015

Posted by **sarah** on Monday, March 2, 2009 at 4:10pm.

(3+i)^2 - 3(3+i)+6

3+2i-9-3i+6

I got 0 - 1i

is this correct or do i use 0

- math -
**Reiny**, Monday, March 2, 2009 at 4:35pmfrom

(3+i)^2 - 3(3+i)+6

= 9 + 6i + i^2 - 9 - 3i + 6

= 3i + 5, remember i^2 = -1

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