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January 30, 2015

January 30, 2015

Posted by **sarah** on Monday, March 2, 2009 at 4:03pm.

2i/4-8i * (4+8i)/(4+8i)

then i multiplied the top and bottom and got

8i/ 4^2 + 16i/8^2

8/80 + 16i/80

reduce to

4/5 + 2i

is this correct

- math -
**Reiny**, Monday, March 2, 2009 at 4:31pmYou started off ok, but then ...

2i/(4-8i) * (4+8i)/(4+8i)

= (8i + 16i^2)/(16 - 64i^2)

= (8i + 16i^2)/(80)

= (i - 2)/10

or

i/10 - 1/5

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