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March 1, 2015

March 1, 2015

Posted by **Meg** on Wednesday, February 4, 2009 at 8:17pm.

Thanks!

- Math -
**bobpursley**, Wednesday, February 4, 2009 at 8:48pm1+2+4+...2^n up to a year in seconds.

That looks like the sum of a geometric series, where r=2

Use that formula, you know the sum is 1*365*24*3600...find the number of terms.

- Math -
**DAS**, Wednesday, February 4, 2009 at 9:11pmit looks like you could just solve for

2^x=(1*365*24*3600)

=>xln(2)=ln(1*365*24*3600) =>

x=ln(1*365*24*3600)/ln(2)

oh and at 1 for the series begining at 1 not zero. appoximately 26 times.

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