Posted by Chopsticks on Wednesday, January 7, 2009 at 10:35pm.
I answered this question in your last post.
yes, which give you
2b(a^2 - 8a + 16)
= 2b(a-4)^2
Who wait, but i thought you cant factor using b because ab is a term by itself
If the b is not part of the exponent, my last response was incorrect.
Well if your talking about the 2a^2b its 2a^2 * b the exponent is only with the a. So does that mean 2b can factor?
Related Questions
Alg 2 - Can someone tell me how to factor 2a^2 - 16ab + 32b I just need someone ...
math,correction - can someone check these for me please.... problem#4 Directions...
Pre-Calc-please check - Please check this for me expand (3z-2b)^5 using Binomial...
algebra 1 - factor 6ab-8b: Common factor: 2b 2b (3a-4)
math,algebra - can someone help me i've tried different numbers but i can ...
honors algebra II - factoring:: i factored 15A^2B - 10AB^2 into... (15A - 10B)(...
alg - Find the sum. Express your answer in simplest form. (14a^2 / 2b) + (3a / ...
dividing with polynomials - solve by using polynomial division(16ab^3c-10ab^2c^2...
Algebra 2 - Factor completely 4ab + 2a + 6b + 3 (2a + 3) (2b + 1)?
algebra - factor 6ab - 8b YOu can factor a 2b out of it.
For Further Reading