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October 25, 2014

October 25, 2014

Posted by **joyce** on Friday, October 31, 2008 at 2:36am.

b) particle A has three times the mass and twice the kinetic energy of particle B. What is the speed ratio VA / VB?

- physics kinetic energy -
**drwls**, Friday, October 31, 2008 at 6:13ama) KE = (1/2) M V^2

What happens to KE when you replace V with a number 4 times larger?

If you can't do that "in your head", try calculating the raio of kinetic energies

KE2/KE1 = (4V)^2/V^2 = ?

b) KEb = KEa/2

KEb/KEa = (Mb/Ma)*(Vb/Va)^2 = 1/2

= (1/3)*(Vb/Va)^2

Solve for Va/Vb

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