posted by Sandhya on .
A 66.0 kg base runner begins his slide into second base when he is moving at a speed of 4 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.
(a) How much mechanical energy is lost due to friction acting on the runner?
(b) How far does he slide?
Wouldn't it be equal the the KEnergy lost? 1/2 mv^2. Then to get the distance, KE=mu*mg*distance.
Thanks for your quick help
bobpursley, what does the mu stand for in your equation?
Mu is the coefficient of friction (μ).