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April 20, 2014

April 20, 2014

Posted by **Vana** on Saturday, September 27, 2008 at 1:28pm.

h(x) = 12x + 3 / 2 - square root over x

a)[0,4)

b) [(0,4) U ( 4, infinity)

I know that hte answer is b, but how do I come to this answer?

- calculus -
**drwls**, Saturday, September 27, 2008 at 7:56pmx cannot be negative (because the square roots of negatove numbers are unreal) and it also cannot cause the denomimator (2 - sqrt x) to be zero. Therefore x cannot be exactly 4, either.

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