Posted by **Aniya** on Sunday, July 13, 2008 at 5:39pm.

A square mirror has sides measuring 2 ft. less than the sides of a square painting. If the difference between their areas is 32 ft^2, find the lengths of the sides of the mirror and the painting?

Square mirror= x-2

Painting=x

I don't know where to go from there...

The dimensions of a HP flat panel monitor are such that its length is 3in more than its width. If the length were doubled and if the width were decreased by 1in. the area would be increased by 150 in^2. What are the length and the width?

I don't know where to start....

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