Math
posted by Susie .
What is the solution for the following system of linear equations?
x + 6y = 4 3x  4y = 10

from the first equation:
x = (6y+4)
substitute that for x in the second equation
3(6y+4) 4y = 10
18y 12 4y = 10
22 y = 22
y = 1
now go back and get x
x = (6*1 + 4)
x =  (2)
x = 2
check
2 + 6*1 = 4 sure enough
3*2 4*1 = 10 yes