Posted by **LT** on Monday, May 5, 2008 at 11:49am.

Ok this is what i got for the grams part now....

Total mass is 20.14 + 51.64 + 11.34 + 15.06 = 98.18

%H2O = (20.14/98.18)*100 = 20.51%

%C2O4 = (51.64/98.18)*100 = 52.60%

% Fe 3+ = (11.34/98.15) * 100= 11.55%

% K + = (15.06/98.15) * 100 = 15.43 %

20.51 g H2O, 52.60 g C2O4 11.55 g Fe 3+, 15.43 g K+

you said redo the mols and percent... can you give me an example of how please

- Dr. Bob Chemistry question -
**DrBob22**, Monday, May 5, 2008 at 12:19pm
Answered below.

- Dr. Bob Chemistry question -
**LT**, Monday, May 5, 2008 at 12:52pm
ok i did all the mols of those numbers and came out with

H2O = (20.51/18.051)=1.136

C2O4 = (52.60/88.016)=.5976

Fe 3+ = (11.55/55.845)= .2068

K + = (15.34/39.098)=.3923

Ive gotten that far... now im a little confused on how you do the rest of the question because they don't come out to whole numbers can you show me an example please

- Dr. Bob Chemistry question -
**DrBob22**, Monday, May 5, 2008 at 1:11pm
Divide all the numbers by the smallest number, in this case that is 0.2068. Then round to the nearest whole number. If you have one that will round to 1/2, then multiply all by 2 to get rid of the 1/2. If you still don't get it, post your values for the division along with what the mols are for; i.e.,

H2O = 5.5 etc.

These numbers aren't coming out with anything I recognize; perhaps the teacher just made up a problem.

- Dr. Bob Chemistry question -
**LT**, Monday, May 5, 2008 at 1:30pm
1.136/.2068=5.5

.5976/.2068= 2.88 so 3

.2068/.2068 = 1

.3923/.2068 = 1.89 so 2

now do i do it to all four with different denominators like

1.136/1.136= 1

.5976/1.136 =

and so on or do i do it by just that one

- Dr. Bob Chemistry question -
**DrBob22**, Monday, May 5, 2008 at 3:10pm
No, you're done, except for multiplying everything by 2 to get rid of the 1/2 in 5.5

So you have

H2O = 5.5 x 2 = 11

C2O4 = 3 x 2 = 6

Fe^+3= 1 x 2 = 2

K^+ = 4

So you have

K4Fe(C2O4)6*11H2O

I don't know what it is but something is wrong here BECAUSE Fe is NOT +3 in this formula, it is +4 and that's not possible. I don't know of ANY compound in which Fe is +4 and this one especially because it's listed in the problem as +3. The potassium ferrioxalate I know about is K3Fe(C2O4)3. Check your numbers in the orginal problemm Make sure your original post is correct.

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