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April 18, 2014

April 18, 2014

Posted by **Kelsey** on Saturday, May 3, 2008 at 11:05pm.

I know ln x + ln (x+3)=ln [x(x+3)] and that is ln x^2 + 3x when broken down. Then you have to get rid of ln by taking the natural base e of both sides so in the end you have x^2+3x = e^(1). That's when I got stuck.

- Pre-Calculus -
**drwls**, Sunday, May 4, 2008 at 5:45amYou are on the right track. Remember that e^1 = e = 2.718..

You just need to use the quadratric equation to solve

x^2 + 3x -2.718 = 0

since it cannot be factored easily.

x = [-3 +/- sqrt (19.87)]/2

= 1.458/2 or -7.458/2 = 0.729 or -3.729

- Pre-Calculus -
**destiny**, Tuesday, November 10, 2009 at 9:23pmx+5=4

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