Posted by **Kelsey** on Saturday, May 3, 2008 at 11:05pm.

I need help solving this logarithmic equation: ln x + ln (x+3) = 1.

I know ln x + ln (x+3)=ln [x(x+3)] and that is ln x^2 + 3x when broken down. Then you have to get rid of ln by taking the natural base e of both sides so in the end you have x^2+3x = e^(1). That's when I got stuck.

## Answer This Question

## Related Questions

- pre-calculus - solve the following logarithmic equation. Be sure to reject any ...
- Pre-Calculus - How do I solve these equations? I need to create an equation ...
- pre-calculus - solve the following logarithmic equation. be sure to reject any ...
- Logarithmic Function - Could you please verify and calculate the following ...
- pre-calculus - Change the logarithmic expression to an equivalent expression ...
- calculus - Please help me? ln(x+1)-ln(x-2)=ln(5) 1. Solve equation by setting up...
- pre-calculus - solve the logarithmic equation. be sure to reject any value of x ...
- Calculus - Find the solution of the logarithmic equation: ln(x+8)+ln(x–8)=0 Im ...
- calculus - Please help me solve this equation. log[2](3)+log[2](x)=log[2](5)+log...
- calculus - solve the logarithmic equation. be sure to reject any value of x that...

More Related Questions