Homework Help: Physics

Posted by Johnson on Friday, April 18, 2008 at 4:28am.

A jogger's internal energy changes because he performs 6.80 105 J of work and gives off 4.9 105 J of heat. However, to cause the same change in his internal energy while walking, he must do 8.10 105 J of work. Determine the magnitude of the heat given off while walking.
J

Physics - Damon, Friday, April 18, 2008 at 5:25am
decrease in U = work done + heat given off
=(6.8 +4.9)*10^5
= 11.7 * 10^5 J
then
11.7*10^5 = 8.1*10^5 + heat given off
heat given off = (11.7-8.1)10^5 = 3.6*10^5 J

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