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April 18, 2014

April 18, 2014

Posted by **shan** on Wednesday, March 19, 2008 at 1:48am.

- physics -
**drwls**, Wednesday, March 19, 2008 at 7:30amIf the collar is a weight on top of the spring, use conservation of energy.

After falling h = 2 feet, the collar has velocity sqrt (2gh) = sqrt(2*32.2*2) = 11.35 ft/s.

The kinetic energy at that point can be set equal to the sum of the kinetic and potential spin energy, plus the loss of additional gravitational PE, after compressing the spring 0.3 ft. You will need the spring constant to compute the new velocity.

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