Monday

March 2, 2015

March 2, 2015

Posted by **Jon** on Friday, March 7, 2008 at 6:25pm.

Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.

(secx/sinx)*(cotx/cscx)

= (secx/cscx)(cotx/sinx)

= (sinx/cosx)*cotx*(1/sinx)

"The last steps should be obvious"

Not to me. I can convert (sinx/cosx) to tanx if that's even what I'm suppose to do. Is (sinx/cosx)*cotx*(1/sinx) the answer?

- drwls -
**Damon**, Friday, March 7, 2008 at 6:57pmI am not sure he is still here

(sinx/cosx)*cotx*(1/sinx)

(sin/cos)*(cos/sin) * (csc)

1 * (csc) = csc

remember csc = 1/sin

- drwls -
**drwls**, Friday, March 7, 2008 at 7:19pmI skipped that step that tanx*cotx = 1

**Answer this Question**

**Related Questions**

trig - express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is ...

Precalculus/Trig - I can't seem to prove these trig identities and would really ...

Math - Verify the identity . (cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant ...

Math - Im really struggling with these proving identities problems can somebody ...

Pre-Calculus - Find a numerical value of one trigonometric function of x if tanx...

Math - Im really struggling with these proving identities problems can somebody ...

trigonometry - can i use factoring to simplify this trig identity? the problem ...

Math - I'm only aloud to manipulate one side of the problem and the end result ...

calculus - express in sinx 1 1 ---------- + -------- cscx + cotx cscx - cotx and...

Trig Help - Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...