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September 18, 2014

September 18, 2014

Posted by **Jon** on Friday, March 7, 2008 at 6:25pm.

Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.

(secx/sinx)*(cotx/cscx)

= (secx/cscx)(cotx/sinx)

= (sinx/cosx)*cotx*(1/sinx)

"The last steps should be obvious"

Not to me. I can convert (sinx/cosx) to tanx if that's even what I'm suppose to do. Is (sinx/cosx)*cotx*(1/sinx) the answer?

- drwls -
**Damon**, Friday, March 7, 2008 at 6:57pmI am not sure he is still here

(sinx/cosx)*cotx*(1/sinx)

(sin/cos)*(cos/sin) * (csc)

1 * (csc) = csc

remember csc = 1/sin

- drwls -
**drwls**, Friday, March 7, 2008 at 7:19pmI skipped that step that tanx*cotx = 1

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