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January 26, 2015

January 26, 2015

Posted by **Jon** on Friday, March 7, 2008 at 1:51pm.

(x=theta BTW)

- Trig -
**drwls**, Friday, March 7, 2008 at 2:25pm(secx/sinx)*(cotx/cscx)

= (secx/cscx)(cotx/sinx)

= (sinx/cosx)*cotx*(1/sinx)

The last steps should be obvious

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