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October 1, 2014

October 1, 2014

Posted by **angie** on Saturday, February 23, 2008 at 8:46pm.

- math -
**Damon**, Saturday, February 23, 2008 at 9:07pmL = 6 h

W = 3 h

(L-2)(W-2)h = 4

(6h-2)(3h-2)h = 4

(18 h^2 - 18 h +4)h = 4

18 h^3 - 18 h^2 + 4 h - 4 = 0

That happens to be zero when h = 1, so that is a solution

If h = 1

L = 6

W = 3

That answers the question, but check to see if there are other solutions

dividing by (h-1)

I get

18 h^2 + 4 = 0

that has imaginary solution, so h = 1 is the only real solution.

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