Posted by angie on Saturday, February 23, 2008 at 8:46pm.
L = 6 h
W = 3 h
(L-2)(W-2)h = 4
(6h-2)(3h-2)h = 4
(18 h^2 - 18 h +4)h = 4
18 h^3 - 18 h^2 + 4 h - 4 = 0
That happens to be zero when h = 1, so that is a solution
If h = 1
L = 6
W = 3
That answers the question, but check to see if there are other solutions
dividing by (h-1)
I get
18 h^2 + 4 = 0
that has imaginary solution, so h = 1 is the only real solution.
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