Posted by **Jon** on Saturday, February 16, 2008 at 1:02pm.

1)Find x in the solution of the system 3x+y=2 and 2x-3y=16

A)2

B)-4

C)18/11

D)10/11

I chose A

3x+y=2 times 3 = 9x+3y=6

2x-3y=16 times 1 = 2x-3y=16

11x/11 = 22/11x = 2

2)Find the coordinates of the vertices of the figures formed by y -< x + 2, x + 2 -< 6, and y >- -2

A)(0,0),(2,4),(8,-2)

B)(-4,-2),(2,4),(8,-2)

C)(-4,-2),(4,2),(8,-2)

D)(-2,-4),(2,4),(8,-2)

I chose B

this one confused me this is all the work to show:

-2 -< -4 + 2

2 + 4 -< 6

-2

- Algebra -
**Reiny**, Saturday, February 16, 2008 at 1:46pm
Your inequations form the boundaries of the figure.

So change the < or > to an equal sign, then solve them in pairs.

You should get 3 sets of intersection points.

Solve the pairs of equations just like you did #1.

- Algebra -
**Jon**, Saturday, February 16, 2008 at 2:05pm
ok im stuck after this:

y = x + 2

x + y = 6

y = -2

- Algebra -
**Guido**, Sunday, February 17, 2008 at 10:55am
I will do number one only.

We have this:

(1)Find x in the solution of the system 3x + y = 2 and 2x -3y = 16.

(A)2

(B)-4

(C)18/11

(D)10/11

Your choice = (A)

We have a system of linear equations in two variables.

Here are the two equations:

3x + y = 2...Equations A

2x -3y = 16...Equation B

I will first isolate y in Equation A.

3x + y = 2

y = -3x + 2....I will plug the quantity (-3x + 2) in Equation B to find the value of x.

2x - 3y = 16

2x - 3(-3x + 2) = 16

2x + 9x - 6 = 16

11x - 6 = 16

11x = 16 + 6

11x = 22

x = 22/11

x = 2

Your choice is correct!

Good job!

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