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November 23, 2014

Homework Help: AP Chemistry

Posted by Jake on Tuesday, February 5, 2008 at 8:35pm.

Could you please review my work and see what i'm doing incorrectly? Thank you

Given this information:

CxHyOz (s) + O2 (g) ----> CO2 + H20

given:
2.165 g of the unknown hydrocarbon
v = 1.868 L
P = 130.2 kPa
T = 65.0 degrees C
g of H2O = 1.818

a)find g H in hydrocarbon
1.18g/18.02 g/mol = .101 mol H20
.101/1.01 g/mol H2 = .1 X 2 = .2 g H

b)find mols CO2 in product then find g of C
PV=nRT
n= PV/RT
(1.28 atm)(1.868 L)/(.0821 L atm/mol K)(338 K)
n= .0863 mols CO2

.0862 mols X 12.01 g/mol = 1.035g C

c) find g O
2.165 g -(.2 g + 1.035) = .93 g O

d) find empirical formula of hydrocarbon
.2/ 1.01 = .198 mol

.93/16.00 = .581 mol

1.035/12.01 = .0862 mol

my mol ratios don't work out correctly

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