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October 20, 2014

October 20, 2014

Posted by **abby** on Saturday, January 26, 2008 at 9:08pm.

This packet deals with Gas Laws.

1. Given 100 ml of dry gas measured at 37° C and 760 mmHg, what would be its volume at 60°C?

I used Charle's Law and solved for V2.

So... (100/310)(333)=107.4ml

correct?

2. Given 100 ml of dry gas at 37°C and 760 mmHg, what would be its volume at 60°C and 800 mmHg?

I used the combined gas law and solved for V2.

So... (760)(100)(333)/(310)(800)=102ml

3. Given 325 ml of saturated gas at 760 mmHg and 25°C, what would be its volume if dry at the same pressure and temperature?

I got confused when I read 'if dry' Does that mean I have to subtract something out of 760mmHg?

And would I used the combined gas law and solved for V2?

Thanks!

- physics (gas laws) (#1 of 3) -
**drwls**, Saturday, January 26, 2008 at 10:06pm1. yes

2. yes

3. There will be less gas when the saturated gas is dried. Subtract the vapor pressure of water at 25 C (23.8 mm Hg) from the 760 mmHg pressure to get the initial dry gas partial pressure. Since the pressure is maintained at 760 mm, that means the volume must be reduced by the fraction (760- initial water vapor pressure)/760

- drwls, question for you. -
**abby**, Saturday, January 26, 2008 at 10:26pmCan you explain to me how you got the vapor pressure of water, the 23.8mmHG?

How did you get that number?

And so the final number component is 0.96?

- drwls, question for you. -
- physics (gas laws) -
**drwls**, Sunday, January 27, 2008 at 3:09amYou have to look up the vapor pressure. See

http://genchem1.chem.okstate.edu/1314SP06/Database/VPWater.html

for example.

Assuming that the gas was saturqated with H2O, the final volume is reduced to 96.9% of the initial volume, or 315 ml.

- physics (gas laws) -
**Anonymous**, Monday, October 22, 2012 at 3:06pm30 cubic meters of argon gas are kept under constant pressure. The gas is heated from 10.0 degrees Celsius to 293 degrees Celsius. What is the new volume of the gas?

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