Posted by abby on Saturday, January 26, 2008 at 9:08pm.
1. yes
2. yes
3. There will be less gas when the saturated gas is dried. Subtract the vapor pressure of water at 25 C (23.8 mm Hg) from the 760 mmHg pressure to get the initial dry gas partial pressure. Since the pressure is maintained at 760 mm, that means the volume must be reduced by the fraction (760- initial water vapor pressure)/760
Can you explain to me how you got the vapor pressure of water, the 23.8mmHG?
How did you get that number?
And so the final number component is 0.96?
You have to look up the vapor pressure. See
http://genchem1.chem.okstate.edu/1314SP06/Database/VPWater.html
for example.
Assuming that the gas was saturqated with H2O, the final volume is reduced to 96.9% of the initial volume, or 315 ml.
30 cubic meters of argon gas are kept under constant pressure. The gas is heated from 10.0 degrees Celsius to 293 degrees Celsius. What is the new volume of the gas?
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