Posted by Anonymous on Thursday, January 17, 2008 at 9:02am.
Consider on number 2 that NaCl breaks into two particles when dissoved, which doubles the effect on colligative properties.
1 is in the right ball park but the wrong direction.
For #1, both salt and sugar lower the vapor pressure of the solution compared to that of pure water. Lowering the vapor pressure of water means that it must be raised to a higher temperature before it reaches 1 atmosphere vapor presure (which is the definition of boiling point for a liquid).
2. The increase in boiling point, the decrease in freezing point, and the change in vapor pressure when a non-volatile solute is dissolved in a volatile solvent, depends solely upon the number of dissolved particles. Mole for mole, sucrose has 1 particle per molecule while NaCl has two particles per molecule. Therefore, a 0.1 M NaCl will increase the boiling point of water almost twice as much as 0.1 M sucrose.
Ok, for number 2: NaCl breaks into 2 particles when dissolved whereas sucrose remains as one. This doubles the van't Hoff factor which means a higher temperature is required for it to vaporize.
Does that make sense?
Re: number one. Is that answer ok?
Your revised number 2 answer is great. No, your original answer to number 1 is not correct. Take another look at my resonse to your number 1.
I hadn't even seen your response DrBob. Thanks! Making more sense to me now.
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