there are 50 question in a test. a student gains 2 marks for a correct anwser and loses 1 mark otherwise. if a student has 76 marks, how many question did he answer incorrectly?

This is fairly easy just use alittle more effort and someone will check your answer.

i = # incorrect (or otherwise) answers

c = # correct answers
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i + c = 50
-1 + 2c = 76
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Solve the two equations simultaneously.
Post your work if you get stuck.

Check my thinking. Check my work.

To answer this question, we can use algebra to set up an equation and solve for the number of incorrect answers.

Let's assume that the student answered x questions correctly. Since there are a total of 50 questions on the test, the number of incorrect answers would be 50 - x.

For each correct answer, the student gains 2 marks, so the total marks gained from the correct answers would be 2x.

On the other hand, for each incorrect answer, the student loses 1 mark, so the total marks lost from the incorrect answers would be 1 * (50 - x), which simplifies to 50 - x.

According to the information given, the student has a total of 76 marks. We can now set up the equation:

2x - (50 - x) = 76

Simplify the equation:

2x - 50 + x = 76

Combine like terms:

3x - 50 = 76

Add 50 to both sides of the equation:

3x = 126

Divide both sides by 3:

x = 42

The student answered 42 questions correctly. Therefore, the number of questions the student answered incorrectly would be:

50 - x = 50 - 42 = 8

So, the student answered 8 questions incorrectly.