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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Sunday, October 21, 2007 at 4:31am.

W=FnetX distance=ma x distance

4500N=(1/2)1400kg V^2

2.5m/s=V

is this right? if not what am i doing wrong?

- COLLEGE PHYSICS -
**bobpursley**, Sunday, October 21, 2007 at 6:10amNo.

Your equations are troubling, as it reveals you have no idea what you are doing.

Work input= KE output

Netforce*distance= 1/2 m v^2

4500*100= 1/2 *1400*v^2

Solve for v. This is about ten times what you thought.

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