February 21, 2017

Homework Help: math

Posted by anonymous on Friday, October 19, 2007 at 9:10pm.

If 90% of the households in a certain region have an answering machines and 50% have both answering machines and call waiting, what is the probability that a household chosen at random and found to have an answering machine also has call waiting?

This is what I think...(Am I correct?)
P(answering and call waiting/answering machine)=(.50/.90)=.56 or 56%

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