Posted by Sarah on Wednesday, October 10, 2007 at 12:39pm.
A 250.0 kg roller coaster car has 20000 J of potential energy at the top of a hill. Neglecting frictional losses, what is the velocity of the car at the bottom of the hill?

Physical Scienceplease help  bobpursley, Wednesday, October 10, 2007 at 12:46pm
The KE will equal the PE at the top
1/2 m v^2= 20000
solve for v.

Physical Scienceplease help  Sarah, Wednesday, October 10, 2007 at 1:05pm
I believe that this answer is 9.8 m/s am I right?

Physical Scienceplease help  bobpursley, Wednesday, October 10, 2007 at 1:29pm
The kinetic energy (1/2 *mass*velocity squared) will equal the potential energy a the top
1/2 m v^{2} = 20000
The veloicity will be near 13 meters/second at the bottom
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