Wednesday

October 1, 2014

October 1, 2014

Posted by **anonymous** on Wednesday, August 30, 2006 at 9:02pm.

|2x+3|< 26

So there are two answers to this problem? Do you switch the inequality sign for the second answer?

This is the absolute value of some quantity I suppose. We have

|2x+3|< 26

Thus we want numbers such that

-26 < 2x+3 < 26

You can split this into two equations requiring x to satisfy both. You could split them like this

-26 < 2x+3

2x+3 < 26 and solve each expression, then take the intersection of the solutions, or add -3 to

-26 < 2x+3 < 26 to get

-29 < 2x < 23 now divide by 2

-26/2 < x < 23/2 or

-13 < x < 11.5 should be the final solution. This is an open interval.

For this problem I used the fact that

|x|< a means -a < x < a.

After reviewing, I see I didn't finsish the problem correctly. We started with |2x+3|< 26

We then have -26 < 2x+3 < 26

Followed by -29 < 2x < 23

The next line has a typo. This is what I had: -26/2 < x < 23/2

It should be: -29/2 < x < 23/2, and the final line should be

-14.5 < x < 11.5

This is the open interval (-14.5,11.5). It has a radius of 13 and is centered at -1.5.

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