olav
Most popular questions and responses by olav
math
Trapezoid ABCD, top and bottom are parallel. Left is 45, bottom is 60, right is 30, top is unknown. Trapezoid EFGH is similar to ABCD, top and bottom are parallel. Top is 10, other sides are unknown. Area of ABCD is 9 times larger than EFGH. What is the
asked on December 11, 2010 
grade 9 math
Trapezoid ABCD, top AD and bottom BC are parallel. AD is the smaller of the two parallel lines. Left AB is 45, bottom BC is 60, right CD is 30, top AD is unknown. Trapezoid EFGH is similar to ABCD, top EH and bottom FG are parallel. EH is the smaller of
asked on December 12, 2010 
math
There is on large rectangle ABCD, top line is AD and bottom is BC. A line is drawn from the top to bottom called GH. A line is drawn from left to right called EF. AEFG is Rectangle 1. EBHF is Rectangle 2. GHCD is Rectangle 3. All three rectangles are
asked on December 11, 2010 
Gr. 9 math
There is one large rectangle ABCD, top line is AD and bottom is BC. A vertical line is drawn from the top to bottom called GH (between points AD and BC). A line is drawn from left to right called EF (between points AB and GH). AEFG is Rectangle 1. EBHF is
asked on December 12, 2010 
Grade 9 Math
There is one large rectangle ABCD, top line is AD and bottom is BC. A vertical line is drawn from the top to bottom called GH (between points AD and BC). A line is drawn from left to right called EF (between points AB and GH). AEFG is Rectangle 1. EBHF is
asked on December 12, 2010 
Gr. 9 Math (continued)
I don't see a problem but I will rewrite the structure. Make two rectangles attached together. Call the first rectangle ABHG (AG top, BH bottom). Call the second rectangle GHCD (HC top, GD bottom). Draw a horizontal line from line AB to line GH and name
asked on December 12, 2010 
math
 4cm  (1)   _____     9cm  (2)  (3)      Rectangle 1 & 2 & 3 are similar. What is the area of Rectangle 3.
asked on December 11, 2010

Gr. 9 Math (continued)
Thank you for all your help.
posted on December 12, 2010 
math
( (5 x 5) x 2 ) + 5 = (25 x 2) + 5 = 55.
posted on December 12, 2010 
Gr. 9 Math (continued)
I looked at it another way. I used rectangle FEBH; area = 9 x EF. I used rectangle AEFG; area = 4 x EF. Ratio of area FEBH to AEFG = 2.25 The square root of area is ratio of the perimeters = 1.5 Perimeter of AEFG = 2 x 9 + 2 x EF Perimeter of FEBH = 2 x 4
posted on December 12, 2010 
Gr. 9 math
I reposted a better structure at 1:58 thank you for your help so far.
posted on December 12, 2010 
Gr. 9 math
I don't see a problem but I will rewrite the structure. Make two rectangles attached together. Call the first rectangle ABHG (AG top, BH bottom). Call the second rectangle GHCD (HC top, GD bottom). Draw a horizontal line from line AB to line GH and name
posted on December 12, 2010 
math
Simple. 250 x (40/100) x (46/100) = 250 x .4 x .46 = 46 applicants will be selected.
posted on December 12, 2010 
Math
look them up using goog.le
posted on December 12, 2010 
Algebra
There is no difference between 12 and 21 if you disregard the + or  in the final answer. Sometimes when I do calculations on the calculator and I forget which number is the larger, I will end up with a negative answer. I just remember that the answer
posted on December 12, 2010 
grade 9 math
Does this work for all trapezoids ? Is this true for all similar enclosed figures ? Can you help me with my other question posted minutes later than this one ?
posted on December 12, 2010 
computer architecture
A word is two bytes. A byte has 8 bits.
posted on December 12, 2010 
grade 9 math
I am still lost. How come the areas of similar figures (trapezoids) are proportional to the squeare of their corresponding perimeters.
posted on December 12, 2010 
math
20 percent is actually 20/100 or .2 87/8 is actually 10.875 The result is .2 x 10.875 or using fractions (20 x 87) / (100 x 8) = 1740 / 800 = 2 140/800 = 2 7/40 or 87/40
posted on December 12, 2010