kay bri
Most popular questions and responses by kay bri
algebra
The first three equations I have solved, I would just appreciate someone checking them over to make sure I'm doing them right. Find the GCF: 16x^2z ,40xz^2 , 72z^3 = 3^3z Factor our GCF: a(a+1)  3(a+1) = a+1 Factor Polynomial: 9a^2  64b^2 =
asked on January 23, 2009

algebra
in the first one: 16x^2z ,40xz^2 , 72z^3 the only question I have is, how can it be 4xz when they don't all have the variable 'x'? the way I factored it was like this: 16x^2z 16 = 8 & 2 x^2z 4&2 (x)(x)(z) 2&2 = 2^4 40xz^2 40 = 10 & 4 xz^2 5&2 2&2 (x)(z)(z)
posted on January 23, 2009