# SANDRO!

Popular questions and responses by SANDRO!
1. ## ALGEBRA 1!PLZ HELP!

Use the Substitution method to solve the system of equations. y - 2x = -5 3y - x = 5 Solve the first equation for y. y = 2x-5 Substitute that for y in the second equation and solve for x. Then use the value of x to substitute back into the first equation

2. ## Math!Algebra!

(-2x^2y)^3 * (5xy^3)^2 What is ^ and * suppose to symbolize? ^=power *=times/multiply (-2x^2y)^3 * (5xy^3)^2 Sorry, I do not recall how to do this. I don't want to misguide you. First remove the parentheses by cubing the first term and squaring the second.

3. ## algerba!2!

(-2x2y)3 * (5xy3)2 *I don't get this on at all!!! Are there any exponents in this one? If so, repost showing the caret to indicate the exponent. oh sorry I forget to do that.LOL!Here it is now: (-2x^2y)^3 * (5xy^3)^2 Are there any exponents in this one? If

4. ## Algebra1234567890!

(-mn8)3 would it be: -m^3n^3164 (-mn8)3 = -24mn Without carrots I have no idea where your exponents are. how?I don't get this one? Is this Sandro from Mrs.Pfeiffer's class?What grade are you in? Leo is saying you need to use carets to show an exponent. As

5. ## Algebra 12345!!!

(5a^3b^4)2 would it be: 10a^6b^8 five squared is 25, and three squared is nine, not ten and six. Sorry!I always forget!LOL! (5a^3b^4)^2 = 5^2 (a^3)^2 (b^4)^2 = 25 a^6 b^8

6. ## Algebra 112

(-3xy^3)^4 Would it be: -81x^4y^12 Almost, but not quite. Just watch your negative signs. So it would be positive? (-)*(-)*(-)*(-)= + right. Thanks

7. ## Algebra

How do I do these powers? (2a5)3 So it is really: (2a^5)^3 Raise each inside the parentheses to the third. 23*(a5)3 = ?? I don't get it!Here is what I got: 2*2*2=8(a^8) *Also how do you do the powers for the numbers on here? almost but not quite. 2*2*2 = 8

8. ## BOBPURSLEY PLZ FINISH HELPIN ME W/MY OTHER PROBLEM

BASICALLY WHAT THE TITLE SAYS!