Physics PLEASE
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Physics PLEASE
I'm trying to solve this problem Calculate (a) how long it took King Kong to fall straight down form the top of the Empire State Building (380 m high), and (b) his velocity just before "landing". My teacher said try and rearagne this equation for t X = Xo
asked on June 23, 2009 
Physics Please
You want to show that V^2  Vo^2 = 2 a (X  Xo) first rewrite that as: (VVo)(V+Vo) = 2a (XXo) now your average velocity during the interval = (V+Vo)/2 so X = Xo + t(V+Vo)/2 but V = Vo + a t so t = (VVo)/a so X = Xo +(VVo)(V+Vo)/2a we are there.
asked on June 19, 2009 
Physics PLEASE
I'm trying to derive the formula v^2 = v0^2 + 2a(xx0) were zeros are subscripts my book tells me to derive it this way use the definition of average velocity to derive a formula for x use the formula for average velocity when constant acceleration is
asked on June 19, 2009 
Physics PLEASE
I'm trying to solve this problem Calculate (a) how long it took King Kong to fall straight down form the top of the Empire State Building (380 m high), and (b) his velocity just before "landing". My teacher said try and rearagne this equation for t X = Xo
asked on June 23, 2009 
Physics PLEASE
Of course you have to rearrange it X Xo = (VVo)(V+Vo)/2a (XXo)2a = (VVo)(V+Vo) 2 a (XXo) = V^2Vo^2 ok to go from the first line to the second line you multiply by 2a I agree but what allows you to just put parenthsess around the XXo Thank You!
asked on June 19, 2009

Physics PLEASE
oh... Xo is not zero
posted on June 23, 2009 
Physics PLEASE
thanks
posted on June 23, 2009 
Physics Please
This is what i did x = 2^1(v0 + v)a^1(vv0) + x0 simplfy x = (a2)^1(v^2 v0^2)+ x0 (x = (a2)^1(v^2 v0^2)+ x0)2a (2a)x = (v^2v0^2) + x0 (2a)x  x0 = (v^2v0^2) + x0  x0 (2a)x  x0 + v0^2= (v^2  v0^2) + v0^2 (2a)x  x0 + v0^2 = v^2 i do not see were
posted on June 19, 2009