# Pd

Most popular questions and responses by Pd
1. ## A lev chem

Comment on the solubility of iodine (I2) in each of the following liquids. State whether at room temperature you expect I2 to be highly soluble or almost insoluble, and choose the appropriate reasons why. HINT: It may behoove you to draw the Lewis

2. ## science-physics

A swimmer, capable of swimming at a speed of 1.97 m/s in still water (i.e., the swimmer can swim with a speed of 1.97 m/s relative to the water), starts to swim directly across a 2.77-km-wide river. However, the current is 1.13 m/s, and it carries the

3. ## Math

need to classify to stationary points as local minimum and local maximum of g(x) got this far 2x-7=0 4x+1=0 so x = 7/2 and x = 1/4 but bit confused on using xL and xR for each to get the local min and max..?

4. ## math

Consider the experiment of drawing two cards without replacement from an ordinary deck of 52 playing cards. #1. What are the odds in favor of drawing a spade and a heart? Coin question... What are the odds in favor of getting at least one head in three

5. ## ICA Honors

1/log_2(X) + 1/log_3(x) + 1/log_4(x) +1/log_5(x) =log_5(625)

6. ## Math

find any stationary points of the function g(x) = (2x-3)square root of 5+16x-4x^2 (0 less than or equal to x less than or equal to 4) and use the first derivative test to classify each stationary point as a local maximum or local minimum of g(x) this is

7. ## math

f(x)=-x^3+3x^2+9x-5 asked to find the stationary points this was my working and i don't know if it is correct f dash of x = -3x^2+3(2x)+9 -3x^2+6x+9 at local max and min f(x) should =0 -3x^2+6x+9=0 3x^2-6x+9 x^2-2x+3=0 stationary points would be at (x+3)

8. ## Math (Bob Pursley

i asked about stationary points which came out at (x-3) and (x+1) i am now trying to use the first derivative test to classify the left hand point... (x-3) so picking an xL point of -4 and an xR point of -1 i get this f ' (-4) = 3 16 - 4 + 9 = 48 - 24 + 9

1. ## A lev chem

Thank you so much for this! sorry the text garbage.. a,b,c were correct while "One component is polar and the other is nonpolar, and therefore they don't have the capability of mixing." just thought you wanted to know, thank you again

posted on August 26, 2014
2. ## Maths

sorry, the answer is 1 :P

posted on April 30, 2013