Zozina
Newest questions and responses by Zozina
Probability
Question:A fair coin is flipped independently until the first Heads is observed. Let the random variable K be the number of tosses until the first Heads is observed plus 1. For example, if we see TTTHTH, then K=5. For K=1,2,3...K, let Xk be a continuous
asked on October 27, 2018 
Probability: Counting
Hi everyone. I am struggling a bit with this one example question I am doing. Problem: There is a group of 12 people, 6 men and 6 women. A committee is to be formed consisting of 5 members from this group. Find the probability that Anne (one of the
asked on September 24, 2018

math
Yes. By definition, the mode is the number that occurs most frequently in the set. Therefore it has to be in the set.
posted on November 19, 2018 
Math
How many letters are there in the alphabet? 26 How many vowels are there in the alphabet? 5 Therefore, the probability of picking one vowel is 5/26. The probability of picking N vowels is (5/26)^N or 5/26 * 5/26 * 5/26.... (N times). So for your question,
posted on November 19, 2018 
Math
@Help Yes that is the right answer.
posted on November 19, 2018 
Probability
Sorry, typo it should be (R+1)^2 there, not (R+1)^1
posted on November 18, 2018 
Probability
@Anonymous, E[((R+1)^1  (R1)^2)/100] = E[4R/100] =1/25 * E[R] = 1/25 * 3.5 = 0.14.
posted on November 18, 2018 
Probability
1) The random circle can only intersect the circle of radius 5 if the centre of the random circle is at most 1 unit away from the circumference of the circle of radius 5. So basically we can draw two boundaries above and below the circle of radius 5. These
posted on November 18, 2018 
Probability
Ok, I know my mistake, I didn't read the question carefully, but was on the right track
posted on October 27, 2018 
Probability: Counting
Oh I simply divide those two results I mentioned, but I am not sure why that works. Because can't, Anne and Billy, be placed in the committee in different ways? 10C3 / 12C5 makes it seem like the ways in which Billy and Anne can be arranged in the
posted on September 25, 2018 
Probability: Counting
Hi Scott. Hmm, I am still unsure what you mean by that. I guess the probability of choosing Anne, in particular, is 1/12, and then the probability of choosing Billy after that becomes 1/11. So maybe 1/12 * 1/11 * (10C3)/(12C5) ? I am quite confused.
posted on September 24, 2018