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use L'Hopital's Rule to evaluate lim (4x(cos 8x-1))/(sin 8x - 8x) as x->0

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  1. calculus

    use L'Hopital's Rule to evaluate lim (4x(cos 8x-1))/(sin 8x - 8x) as x->0

  2. calculus

    Use l'hopital's Rule to evaluate lim x in 0 of (4x(cos 6x-1 )) / sin 3x-3x

  3. Calculus

    yes! tnk u ok? It's actually (x->0.) Find the limit of cot(x)-csc(x) as x approached 0? Lim [cot(x) - csc (x)] ..x->0 = Lim [(cos x -1)/sin x] ..x->0 Use L'Hopital's rule and take the ratio of the derivatives: Lim (-sin x/cos x) = 0 x->0 thank you very

  5. Math - Limits

    Find the limit of f(x) as x approaches 0. f(x) = [1-cos^2(3x)] / x^2 Is there a way to do this if we haven't learned L'Hopital's rule yet? Can we rewrite 1-cos^2(3x) as sin^2(3x), and then use the basic limit: lim x→0 sin(x) / x = 1? Thank you!

  6. L'Hopitals Rule

    5) Use the L’Hopital’s method to evaluate the following limits. In each case, indicate what type of limit it is ( 0/0, ∞/∞, or 0∙∞) lim x→2 sin(x^2−4)/(x−2) = lim x→+∞ ln(x−3)/(x−5) = lim x→pi/4 (x−pi/4)tan(2x) =

  7. Math

    Evaluate: (without using Hopital's rule) d) lim (6-3x)/(((5x+6)^1/2)-4) x->2

  8. math

    i need some serious help with limits in pre-calc. here are a few questions that i really do not understand. 1. Evaluate: lim (3x^3-2x^2+5) x--> -1 2. Evaluate: lim [ln(4x+1) x-->2 3. Evaluate: lim[cos(pi x/3)] x-->2 4. Evaluate: lim x^2+x-6/x^2-9 x--> -3

  10. calculus

    Using L'Hôpital's rule, evaluate lim of xe^(-x) as x approaches infinity

  11. math

    Evaluate using L'Hopital Rule? lim as x approaches x from left (1-x)^(3/x)

  12. calculus

    Evaluate: (without using Hopital's rule) d) lim (6-3x)/(((5x+6)^1/2)-4) x->2 ^ | square root

  13. Calculus

    Hello, I am working on my calc 1 homework where we use L'Hôpital's rule to evaluate limits. When I try to evaluate this problem to find the indeterminate form, it becomes undefined so I know I need to rewrite it in a different way, I just don't know how.

  15. Calculus L'Hopital Rule

    lim x->0 (x)sin(x)/1-cos(x). They both go to 0 so 0/0. now take L'H and product rule of top? lim x->0 (1)sin(x)+ cos(x)(x)/1-cos(x) what next? how do i solve from here?

  16. math

    evaluate without using L'Hopital theorem the following limit lim x-->0 [(sin(x)-x)/(x-tan(x))] the answer is 0.5 but I want to know the steps to calculate such a problem

  17. math

    evaluate without using L'Hopital theorem the following limit lim x-->0 [(sin(x)-x)/(x-tan(x))] the answer is 0.5 but I want to know the steps to calculate such a problem

  18. TRIG!

    Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 x = (sin^2x)^3 +

  20. Calculus

    This is a question related to L'hopital's rule. lim x -> -infinity of ((x)(e^x)) This thing is weird because I apply l'hopital's rule yet I never receive the correct answer which is supposedly = 0. It just stays in the form [-infinity * -infinity]. Anyone

  21. calculus

    This is a question related to L'hopital's rule. lim x -> -infinity of ((x)(e^x)) This thing is weird because I apply l'hopital's rule yet I never receive the correct answer which is supposedly = 0. It just stays in the form [-infinity * -infinity]. Anyone

  22. Calculus

    Evaluate as limit approaches 0. (Without using l'hopital's rule. ( Sqrt(4+sin(x))-2 ) / (3x)

  23. calculus

    Evaluate lim->4 sin(2y)/tan(5y) Here is what I have so far. I am not sure the next steps. Can someone help me? 1. sin(2y)/(sin(5y)*cos(5y)) 2. (sin(2y)*cos(5y))/sin(5y)

  25. Limit Calculas

    Evaluate lim->4 sin(2y)/tan(5y) Here is what I have so far. I am not sure the next steps. Can someone help me? 1. sin(2y)/(sin(5y)*cos(5y)) 2. (sin(2y)*cos(5y))/sin(5y)

  26. calculus

    I have to help teach this class tomorrow for my Senior Seminar Math class. The lesson is over Exponential and Logarithmic Functions and L'Hospital's Rule. I have all the problems needed to review this lesson, but i can not solve any of them. My teaching

  27. calculus

    using L'Hospital's rule, evalutate; LIM as x->0 e^x +cos x / e^x + sin x I'm at LIM x->0 e^x+cosx / e^x +sinx but now I at a lost as to how to proceed.

  28. Calculus-Limits

    Okay, i posted this question yesterday, however, I did not really understand the answer I received. If your the one who answered my question, could you please elaborate. If not, could you try to answer this tough, for me, question. Thanks a lot. lim x-->0

  30. limit calc question

    2 questions!!! 1. Limit X approaching A (X^1/3-a^1/3)/ x-a 2. LiMIT x approaching 0 (1/3+x – 1/3) /x On the first, would it help to write the denominator (x-a) as the difference of two cubes ((x^1/3 cubed - a^1/3 cubed) second. use LHopitals rule. Take

  31. tigonometry

    expres the following as sums and differences of sines or cosines cos8t * sin2t sin(a+b) = sin(a)cos(b) + cos(a)sin(b) replacing by by -b and using that cos(-b)= cos(b) sin(-b)= -sin(b) gives: sin(a-b) = sin(a)cos(b) - cos(a)sin(b) Add the two equations:

  32. algebra

    Can someone please help me do this problem? That would be great! Simplify the expression: sin theta + cos theta * cot theta I'll use A for theta. Cot A = sin A / cos A Therefore: sin A + (cos A * sin A / cos A) = sin A + sin A = 2 sin A I hope this will

  33. Calculus

    Below are the 5 problems which I had trouble in. I can't seem to get the answer in the back of the book. Thanks for the help! lim (theta-pi/2)sec(theta) theta->pi/2 Answer: -1 I am not sure what to do here. lim (tan(theta))^(theta) theta->0+ Answer:1

  35. Calculus

    Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent). I know how to find the indefinite integral of csc(x) dx, but I do not know how to evaluate the improper integral, at the following particular step. I know

  36. calc

    Use L’Hopital’s rule to find the limit of this sequence (n^100)/(e^n) ...If you do L'Hop. Rule it would take forever, right? You would always get an (e^n) at the bottom and will have to use the L'Hop. rule 100 times to find the limit...100*n^99,

  37. Calc Limits

    lim (1+x)^1/x. Give an exact answer. x->0 This reads: The limits as x approaches zero is (1 plus x) to the 1 divided by x. The log of each term is (1/x) ln (1 + x) = ln (1+x)/x Using L'Hopital's rule for the limit of f(x)/g(x), the limit if the log is lim

  38. Calculus

    lim x -> pi/2 (sin(x/2)-cos(x/3)) Evaluate Please help

  40. trig

    Reduce the following to the sine or cosine of one angle: (i) sin145*cos75 - cos145*sin75 (ii) cos35*cos15 - sin35*sin15 Use the formulae: sin(a+b)= sin(a) cos(b) + cos(a)sin(b) and cos(a+b)= cos(a)cos(b) - sin(a)sin)(b) (1)The quantity = sin(145-75) = sin

  41. Math

    Evaluate *Note - We have to find the exact value of these. That I know to do. For example sin5π/12 will be broken into sin (π/6) + (π/4) So... sin 5π/12 sin (π/6) + (π/4) sin π/6 cos π/4 + cos π/6 sin π/4 I get all those steps. The part I am

  42. calculus

    find the limit without using L'Hopital's Rule Lim(X->-4) (16-x^2 / x+4)

  43. Calculus

    find the limit. use L'Hopital's Rule if necessary. lim (x^2+3x+2)/(x^2+1) x -> -1

  45. Mathematics - Trigonometric Identities

    Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y +

  46. limits

    what is the derivative of e^(3*ln(x^2)) i keep getting 6/x * e^(3*ln(x^2)) but that's not one of the multiple choice so am i doing something wront. also, what is the limit of (1-cosx)/(2*(sinx)^2) as x approaches zero. is the answer zero or nonexistent The

  47. Calculus

    If f(x) and g(x) are differentiable and lim(x->a) f(x)/g(x) exists, does it follow that lim(x->a) f '(x)/g'(x) exists (a converse to l'Hopital's Rule)?

  48. Precalculus

    Use one of the identities cos(t + 2πk) = cos t or sin(t + 2πk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(19π/4) (b) sin(−19π/4) (c) cos(11π) (d) cos(53π/4) (e) tan(−3π/4) (f) cos(π/4) (g) sec(π/6+ 2π)

  50. Calculus

    Following 2 questions are from a book at a point where L’Hopital’s Rule, Squeeze Theorem etc. have not been discussed and limits (A) and (B) as given below are to be evaluated by simple methods like algebraic simplification etc. 1. Int. of (xlogx)dx

  51. Calculus

    Following 2 questions are from a book at a point where L’Hopital’s Rule, Squeeze Theorem etc. have not been discussed and limits (A) and (B) as given below are to be evaluated by simple methods like algebraic simplification etc. 1. Int. of (xlogx)dx

  52. Calculus

    lim (arccsinx)(cotx) x-->0+ How do I solve this limit using L'Hopital's rule?

  53. Calculus

    Using L'Hopital's Rule, find the limit: lim x->0+ (as x approaches 0 from the right) of sinx/x^(1/3)

  55. Calculus

    L'hopital's question below: lim x -> 0 from the positive direction of ( 5^(sin(x)) - 1 )/ (x)

  56. calculus, limits, l'hopital

    Using l'hopital's rule, find the limit as x approaches zero of (e^(6/x)-6x)^(X/2) I know l'hopital's rule, but this is seeming to be nightmare. I just don't seem to get anywhere. I mistyped the first time I posted this question.

  57. Calculus

    Using L'Hopital's rule find the limit if exists of; lim x->1 (cosx)/(pi-2x) I got (sinx)/2 but i am not sure about this> Can anyone help me out

  58. CALCULUS!! OH DEATH!!!

    I need to solve: Lim as x is approaching 1/4, for (4x-1)/(1/ ([square root of x] minus 2)). Help would be greatly appreciated!!! It's trivial using L'Hopital's rule. Answer: -64 Correction, the answer is -1. what is l'hospital rule?

  60. Pre Calculus

    Use one of the identities cos(t + 2ðk) = cos t or sin(t + 2ðk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(17ð/4) (b) sin(−17ð/4) (c) cos(17ð) (d) cos(45ð/4) (e) tan(−3ð/4) (f) cos(7ð/4) (g) sec(ð/6+2ð)

  61. Pre Calculus

    Use one of the identities cos(t + 2ðk) = cos t or sin(t + 2ðk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(17ð/4) (b) sin(−17ð/4) (c) cos(17ð) (d) cos(45ð/4) (e) tan(−3ð/4) (f) cos(7ð/4) (g) sec(ð/6+2ð)

  62. calculus, limits, l'hopital

    Using l'hopital's rule, find the limit as x approaches infinity of (e^(6/x)-6x)^(X/2) I know l'hopital's rule, but this is seeming to be nightmare. I just don't seem to get anywhere.

  63. Calclulus - L'Hopital's Rule

    Evaluate the limit as x -> Infinity [5x-sqrt(25x^2+4x)] Direct substitution yields the indeterminate form Infinity - Infinity. Apparently, according to text book, I have to change that mess into something I can use L'Hopital's Rule on. Except the only

  65. Integration?

    Sorry, i have a load of questions on integration... thanks for any help provided! Evaluate the integrals: limit 0 to pi/4 ∫ [sec^2x]/[5+tanx] dx limit 0 to pi/6 ∫ [3cos3x]/[3+sin3x] dx limit 0 to 3 ∫ [2x-1]/[x^2-x+1] dx

  66. Math

    Show using integration by parts that: e^3x sin(2x)dx = 4/26 e^3x (3/2 sin(2x) - cos(2x)) +c Bit stuck on this. Using rule f udv = uv - f vdu u = e^3x dv + sin(2x)dx f dv = v du/dx = 3e^3x v = -1/2 cos(2x) so uv - f vdu: = (e^3x)(-1/2 cos(2x)) - (-1/2

  67. Calculus

    Can someone help find limit using l'hopital rule lim x → ∞ ((3x-4)/(3x+2))^(3x+1), I'm trying to solve by adding ln function to both side.

  68. Calculus

    I am trying to solve the following L'hopital's limits question below: lim x -> 0 from the positive direction of ( 5^(sin(x)) - 1 )/ (x)

  70. Calculus

    Can you please help me get the solution to this limit without using squeeze theorem and l'hopitals rule lim x to 0 of x^3 sin(1/x) lim x to 0 of x^2 sin^2(1/x)

  71. pre-cal

    Simplify the given expression........? (2sin2x)(cos6x) sin 2x and cos 6x can be expressed as a series of terms that involve sin x or cos x only, but the end result is not a simplification. sin 2x = 2 sinx cosx cos 6x = 32 cos^6 x -48 cos^4 x + 18 cos^2 x -

  72. calculus

    using the squeeze theorem, find the limit as x->0 of x*e^[8sin(1/x)] what i did was: -1

  73. Calculus

    Evaluate ∫ (cos(x))^(1/2)sin(x)dx Let u = cos(x)? ∫ (u)^(1/2)sin(x)dx = ∫ [2u^(3/2)/3]sin(x)dx ∫ [2cos(x)^(3/2)/3] (-cos(x)) dx? I thought this involved the FTC, but now I'm thinking that's false.

  75. calculus

    use l'hopital rule on sin(x)/x. x=0

  76. Precal

    I do not understand how to do this problem ((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1 - sin A cos A note that all the trig terms are closed right after there A's example sin A cos A = sin (A) cos (A) I wrote it out like this 0 = - sin^6 A - cos^6 A +

  77. math

    Prove that for all real values of a, b, t (theta): (a * cos t + b * sin t)^2

  78. Calculus..more help!

    I have a question relating to limits that I solved lim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by (1+cosx) to get lim(x->0) (1-cos^2x)/2x^2(1+cosx) = lim(x->0)sin^2x/2x^2(1+cosx) the lim(x->0) (sinx/x)^2 would =1 I then substituted

  80. Calculus

    Evaluate the integral. S= integral sign I= absolute value S ((cos x)/(2 + sin x))dx Not sure if I'm doing this right: u= 2 + sin x du= 0 + cos x dx = S du/u = ln IuI + C = ln I 2 + sin x I + C = ln (2 + sin x) + C Another problem: S ((sin (ln x))/(x)) dx I

  81. trig

    it says to verify the following identity, working only on one side: cotx+tanx=cscx*secx Work the left side. cot x + tan x = cos x/sin x + sin x/cos x = (cos^2 x +sin^2x)/(sin x cos x) = 1/(sin x cos x) = 1/sin x * 1/cos x You're almost there. thanks so

  82. calculus

    Lim sin2h sin3h / h^2 h-->0 how would you do this ?? i got 6 as the answer, just want to make sure it's right. and i couldn't get this one (use theorem 2) lim tanx/x x-->0 and also this one (use squeeze theorem to evaluate the limit) lim (x-1)sin Pi/x-1

  83. Evaluating limits

    Evaluate the limit. (If you need to use - or , enter -INFINITY or INFINITY.) lim x +sin(x)/(2x+cos(x)) as x goes to 0.

  85. Math

    Evaluate the integral of (e^2x)*sin^3 x dx I let u = e^2x, du = (1/2)e^2x dx v= (-1/3)cos^3 x , dv =sin^3 x dx When I used integration by parts and solved it all out I got: (37/36)intgral of (e^2x)*sin^3 x dx = (-1/3)(e^2x)*cos^3 x + (1/18)(e^2x)*sin^3 x

  86. math

    Evaluate. 1. sin^-1(-1/2) 2. cos^-1[(-root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1)

  87. Trig

    Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v - u) tan (v + u) First compute or list the cosine and sine of both u and v. Then use the combination rules sin (v + u) = sin u cos v + cos v sin u. cos (v - u) = cos u

  88. another please help me check~calculus maths

    y=3e^(2x)cos(2x-3) verify that d^2y/dx^2-4dy/dx+8y=0 plz help me i tried all i could but it become too complicated for me here set u=3e^(2x) v=cos(2x-3) du/dx=6e^(2x) i used chain rule dv/dx=-2sin(2x-3) dy/dx=-3e^(2x)sin(2x-3)+cos(2x-3)6e^(2x) d^2y/dx^2

  90. calculus

    1. integral -oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it

  91. Mathematics - Trigonometric Identities - Reiny

    Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm (sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should have been (sinx - 1 + cos^2x) (sinx + 1 - cos^2x) and then the next line should be sin^2x + sinx - cos^2xsinx - sinx - 1 +

  92. MATHEMATICS

    evaluate :- lim (existing from n to infinity)1/n^2 [1/1+cos(pie/2n) +2/1+cos(2pie/2n) + 3/1+cos(3pie/2n)+......to n terms]

  93. Trigonometry

    Solve the equation for solutions in the interval 0

  95. Calculus 1

    Evaluate the following limits after identifying the indeterminate form. Use Hospital's rule. d) lim x_0+ (xe^(2x) + 1)^(5/x) e) lim x_(Pi/2)+ (1 + sec3x)^(cot3x) Thank you!

  96. calculus

    Evaluate the following limits after identifying the indeterminate form. Use Hospital's rule. d) lim x_0+ (xe^(2x) + 1)^(5/x) e) lim x_(Pi/2)+ (1 + sec3x)^(cot3x) Thank you!

  97. need help calculus plz plz-sir steve

    if y=3e^(2x)cos(2x-3) verify that d^2y/dx^2-4dy/dx+8y=0 plz help me i tried all i could but it become too complicated for me here set u=3e^(2x) v=cos(2x-3) du/dx=6e^(2x) i used chain rule dv/dx=-2sin(2x-3) dy/dx=-3e^(2x)sin(2x-3)+cos(2x-3)6e^(2x) d^2y/dx^2

  98. CALCULUS - need help!

    Determine the limit of the trigonometric function (if it exists). 1. lim sin x / 5x (x -> 0) 2. lim tan^2x / x (x ->0) 3. lim cos x tan x / x (x -> 0)

  100. trig integration

    s- integral endpoints are 0 and pi/2 i need to find the integral of sin^2 (2x) dx. i know that the answer is pi/4, but im not sure how to get to it. i know: s sin^2(2x)dx= 1/2 [1-cos (4x)] dx, but then i'm confused. The indefinite integral of (1/2) [1-cos

  101. Math

    If f(x)= {-5x+5x^2 -1

  102. calculus (limits)

    lim h>0 sqrt(1+h)-1/h not sure how to factor this; not allowed to use L'Hopital's Rule. (that isn't taught at my school until Calc II & I'm in Calc I).

  103. Precalc/Trig

    evaluate the expression assuming that cos(x)=1/7, sin(y)=1/3, sin(u)=2/5 and cos(v)=1/3. what is cos(u+v)? sin(x-y)? and tan(u-v)?

  105. calculus

    The limit represents the derivative of some function f at some number a. Select an appropriate f(x) and a. lim (cos(pi+h)+1)/h h->0 answers are f(x) = tan(x), a = pi f(x) = cos(x), a = pi/4 f(x) = cos(x), a = pi f(x) = sin(x), a = pi

  106. calculus

    The limit as x approaches infinity of (e^x+x)^(1/x). I got that it diverges, but I'm not sure if I made a mistake. My work: lim(e+x^(1/x)) lim(e+(1/x^x)) lim(ex^x+1)/x^x l'hopital:lim(e^(e(lnx+1))+1)/e^(lnx+1) diverges?

  107. Exact value

    How to find the exact value of lim (2^h - 1)/ h h->0 Thanks in advance. If you use lim dx->0 of [f(a + dx) - f(a)]/dx = f'(a) and recognize 1=20 [20+dx - 2

  108. math;)

    Show that sin(x+pi)=-sinx. So far, I used the sum formula for sin which is sin(a+b)=sin a cos b+cos a sin b. sin(x+pi)=sin x cos pi+cos x sin pi I think I am supposed to do this next, but I am not sure. sin(x+pi)=sin x cos x+sin pi cos pi If that is right

  110. Calculus 12th grade (double check my work please)

    1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y C.-2/3tan (2x/3y) D.-2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) with respect to x. A.-sin (2x) B.-2x

  111. Trigonometry

    Please review and tell me if i did something wrong. Find the following functions correct to five decimal places: a. sin 22degrees 43' b. cos 44degrees 56' c. sin 49degrees 17' d. tan 11degrees 37' e. sin 79degrees 23'30' f. cot 19degrees 0' 25'' g. tan

  112. math

    Can you please check my work. A particle is moving with the given data. Find the position of the particle. a(t) = cos(t) + sin(t) s(0) = 2 v(0) = 6 a(t) = cos(t) + sin(t) v(t) = sin(t) - cos(t) + C s(t) = -cos(t) - sin(t) + Cx + D 6 = v(0) = sin(0) -cos(0)

  113. calc bc (condensed

    is the limit as x approaches 0 of sin3x over 3x equal to zero? sorry-- basically this is my problem: lim [sin 3x / 4x) x-> 0 ~~~~I multiplied& eventually got to .75* lim (sin 3x / 3x) x-> 0 ~so i figured since (lim (sinx/x) x-> 0 was equal to zero, then

  115. math

    Evaluate. 1. sin^-1(-1/2) 2. cos^-1[(-root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1) I got these values as my answers: 1. -pi/6 2. 5pi/6 3. pi/6 4. 2/3 5. 2pi 6. 0 Can someone please tell me if they are right? thank

  116. Trig

    Find sin(s+t) and (s-t) if cos(s)= 1/5 and sin(t) = 3/5 and s and t are in quadrant 1. =Sin(s)cos(t) + Cos(s)Sin(t) =Sin(1/5)Cos(3/5) + Cos(-1/5)Sin(3/5) = 0.389418 Sin(s-t) =sin(s)cos(t) - cos(s)sin(t) =sin(-3/5)cos(1/5) - cos(1/5)sin(3/5) =Sin-3/5

  117. Calculus

    How would I solve the limit for this sequence. [n^(2)]*[1-cos(2.4/n)] I used L'Hopital's rule by putting n^(-2) in the bottom, but I got the wrong answer of -1.44 in the end. Please help, thanks!

  118. Math

    Solve this equation algebraically: (1-sin x)/cos x = cos x/(1+sin x) --- I know the answer is an identity, and when graphed, it looks like cot x. I just don't know how to get there. I tried multiplying each side by its conjugate, but I still feel stuck.

  120. Trigonometry (Help and Check)

    Evaluate (exact answers): a) sin^-1(cos30) Need help. What do I do? b) sin[(cos^-1((sqrt2)/(2)))+[(sin^-1((sqrt2)/(2)))] = sin(45+45) = sin90 = 1 Is this correct? c) cos(arctan5/7) = 7/(sqrt74) = (7sqrt74)/74 Is this correct? Please and Thank you!

  121. maths

    Choose the option that gives an expression for the indefinite integral ʃ (cos(4x) + 2x^2)(sin(4x) − x) dx. In each option, c is an arbitrary constant. Options A cos(4x) + 2x^2 +c B -1/8cos(4x) + 2x^2)^2 +c C 1/4 (sin(4x) − x)^2 + c D (1/(2 (sin(4x)

  122. Math

    Evaluate the integral of 5^t * sin (5^t) *dt I started out with u = 5^t , but then I got stuck on du because I am not sure how to take the derivative of 5^t? The answer from the book is (-1/ln5) cos(5^t) + C I understand the part with the antiderivative of

  123. maths

    Choose the two options which are true for all values of x 1) cos (x) = cos ( x – pie/2) 2) sin (x + pie/2) = cos (x – pie/2) 3) cos (x) = sin (x – pie/2) 4) sin (x) = sin (x + 4pie) 5) sin (x) = cos (x – pie/2) 6) sin^2 (x) + cos^2 (x) = pie would

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    Trigonometry : Practical application. If x is an acute angle, and tan x = 3\4, evaluate. cos x - sin x \cos x + sin x

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