# let f(x) = Sec (x) in the interval 0

8,530 results
1. ## algebra. help!

Start from 110 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is travelling at a constant rate of 30 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|110-30t| at

2. ## Bubbles

starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. THe distance between the bicycle and the checkpoint is given by the equation d= [105-35t] at

3. ## Math

Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|. At

4. ## Trig

How do I solve the following? sec 3 theta/2 = 2 on the interval 0

5. ## Trigonometry

Find all solutions of the equation in the interval [0,2pi). sec(theta)+2=0 Write your answer in radians in terms of pi

6. ## Science

a ball is thrown upward at a speed of 12 m/s. It will reach the top of its path in about: a) 0.6 sec b) 1.2 sec c) 1.8 sec d) 2.4 sec Please explain how you find the answer!!! I cannot figure it out

7. ## Calculus

Solve: The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds. Find the particle's velocity at t=1 sec. A) 2/3 m/sec B) 4/3 m/sec C) -1/3 m/sec D) 1/6 m/sec Thank you!

8. ## Trig

Solve the equation on the interval 0 less than or equal 0 < 2pi. 1. sec 30/2 = -2 2. cos(20 - pi/2) = -1 3. tan(0/2 + pi/3) = 1

9. ## CaLC AB

1. For f(x)=sin^(2)x and g(x)=0.5x^2 on the interval [-pi/2,pi/2], the instantaneous rate of change of f is greater than the instantaneous rate of g for which value of x? a. 0 b. 1.2 c. 0.9 d. 0.8 e. 1.5 2. if tan(x+y)=x then dy/dx=?? a. tan^2(x+y) b.

10. ## Math

Find all the solutions of the equation in the interval {o,2pi) sec^2x+tanx=1

11. ## solving trig. equations

tan(3x) + 1 = sec(3x) Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes secx and... secx = secx sec(3x) = sec(3x) [just put 3x back in for x- you don't really have to change 3x to x but it kinda makes

12. ## physics

A model sailboat is slowly sailing west across a a pond at.33m/s. a gust of wind blowing at 28 degrees south of west gives the sailboat a constant acceleration of magnitude .30m/s squared during the time interval 2.0 sec. if the net force during the

13. ## Math

Starting from 105 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 35 feet per second. The distance between the bicycle and the checkpoint is given by the equation d = 105 - 35t.

14. ## physics

while cruising along dark stretch of highway at a speed of 25 m/s you see that bridge ahead has been washed out. you apply the breaks to and come to a stop in 4.0 sec construct the position vs time graph and acceleration vs time graph and motion graph for

15. ## Math

The height (in feet) of a small weight oscillating at the end of a spring is h(t) = 0.5 cos(2t) where t is in seconds, 0 ≤ t ≤ 5. (This is calculus. Use radians!) (a)Calculate the weight’s average velocity over the time interval 1 ≤ t ≤ 3. Show

16. ## science/ velocity

a body moves along a straight line,its distance from the origin at any instant being given by the equation x= 8t -3t squared, where x is in centimeter and t is in seconds. find the average velocity of the body in the interval from t=0 to t=1 sec,and in the

17. ## calculus multiple choice

1.The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-axis. What is the volume of the generated solid? a: 0.906 b:0.795 c:2.846 d: 2.498 2.Find the average value of f(x)=2/x over

18. ## Math

What effect will an outlier have on a confidence interval that is based on a small sample size? A) The interval will be smaller than an interval without the outlier. B) The interval will be the same with or without the outlier. C) The confidence interval

19. ## physics

A body thrown vertically up from the ground passes the height 10.2m twice at an interval of 10 sec. Its initial velocity was (g = 10 m/s2)

20. ## Physics

A wheel turns through 90.0 revolutions in 15.0 sec. The angular speed at the end of this 15.0 sec period is 10.0 rev/s. Assuming that the angular acceleration is constant, calculate a) the angular speed at the beginning of the 15.0 sec interval, and b) the

21. ## calculus

Let f(x)=1x^3+2.5x+3. In this problem you will estimate f'(-3) by computing the average rate of change of f(x)over a small interval. Round your answers to three decimal places. 1. First choose the interval of length .1 with -3 being the left endpoint of

22. ## Physics

A spherical satellite has 12 identical monopropellant thrust chambers for attitude control with the following performance characteristics: thrust (each unit): 5 lbf; Is (steady state or more than 2 sec): 240 sec; Is (pulsing duration 20 msec): 150 sec; Is

23. ## Calculus

Sorry this is really long. Just wondering how I would do each of these A particle is moving with velocity v(t) = t^2 – 9t + 18 with distance, s measured in meters, left or right of zero, and t measured in seconds, with t between 0 and 8 seconds

24. ## AP Calculus AB

For an object whose velocity in ft/sec is given by v(t) = -t^2 + 6, what is its displacement, in feet, on the interval t = 0 to t = 6 secs? -36 36 0 55.596 For an object whose velocity in ft/sec is given by v(t) = -2t^2 + 4, what is its distance travelled,

25. ## Math 160

The position function of an object moving along a straight line is given by s = f(t). The average velocity of the object over the time interval [a, b] is the average rate of change of f over [a, b]; its (instantaneous) velocity at t = a is the rate of

26. ## Math

The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per second is f (t) = -16t^2 + 80t + 6. According to Rolle's Theorem, what must be the velocity at some time in the interval (2, 3)?

27. ## Chemistry Ap

A sprinter completes the 100 yard dash in 9.30 seconds. How long would it take her to complete 100. meters if she continued at the same speed? 1. 10.2 sec 2. 10.9 sec 3. 10.7 sec 4. 9.30 sec

28. ## Physics

An airplane originally at rest on a runway accelerates uniformly at 6.2 m/s2 for 12 sec. During this 12 sec-interval the air plane travels an approximate distance of?

29. ## Calculus

Given f '(x) = (x − 4)(4 − 2x), find the x-coordinate for the relative maximum on the graph of f(x). a) 12 m/sec; 22 m/sec^2 b) 22 m/sec; 18 m/sec^2 c) 22 m/sec; 6 m/sec^2 d) 14 m/sec; 3 m/sec^2

30. ## Math

Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|. At

1.) which of the following represents dy/dx when y=e^-2x Sec(3x)? A.3e^-2x sec(3x) tan (3x)-2e^-2x Sec(3x)

32. ## Physics

A spherical satellite has 12 identical monopropellant thrust chambers for attitude control with the following performance characteristics: thrust (each unit): 5 lbf; Is (steady state or more than 2 sec): 240 sec; Is (pulsing duration 20 msec): 150 sec; Is

33. ## math

When making a statistical inference about the mean of a normally distributed population based on a sample drawn from that population, which of the following statements is correct, all else being equal? The 68% confidence interval is wider than the 90%

34. ## physics help

The magnitude of the velocity of a particle which starts from rest 2 ft below the origin when t = 0 and moves along a vertical axis is directly proportional to the time after starting. The displacement of the particle during the time interval from t = 1

35. ## Calculus AP

I'm doing trigonometric integrals i wanted to know im doing step is my answer right? ∫ tan^3 (2x) sec^5(2x) dx =∫ tan^2(2x) sec^4(2x) tan*sec(2x) dx =∫ (sec^2(2x)-1)sec^4 tan*sec(2x) dx let u=sec x, du= 1/2 tan*sec(2x) dx =1/2∫ (u^2(2x)-1) u^4 du

36. ## calculus (check my work please)

Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] dx ∫

37. ## Math

starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. The distance between the bicycle and the checkpoint is given by the equation d= [105-35t] at

38. ## HELPPPPPPP (TRIG)

solve the equation 2 sec x- tan x = cot x for the interval 0 to 360 please:)

39. ## Math

Solve: 3csc^2x - 5cscx - 2 = 0 sec^2x + 5secx + 6 = 0 interval : [0, 2pi]

40. ## Calculus

Let f(x)=1x^3+2.5x+3. In this problem you will estimate f'(-3) by computing the average rate of change of f(x)over a small interval. Round your answers to three decimal places. 1. First choose the interval of length .1 with -3 being the left endpoint of

41. ## Calculus

For an object whose velocity in ft/sec is given by v(t)=2sin(t),what is its distance,in feet, travelled on the interval t=1 to t=5?

42. ## Calculus

(I know it looks like a lot but it's just 10 questions) (part 1 [It also explains my situation]: jiskha.com/questions/1788952/Hi-I-missed-school-due-to-illness-and-my-school-isnt-very-forgiving-so-I-would) (If your willing to do this part along with part

43. ## Chemitry

Nitrogen dioxide, NO2, decomposes upon heating to form nitric oxide and oxygen according to the following equation: 2NO2(g)---->2NO(g) + O2(g) At the beginning of an experiment, the concentration of nitrogen dioxide in a reaction vessel was 0.1103 mol/L.

44. ## science

the change in velocity takes place in 10 sec interval. What is the magnitude, the algebraic sign and the direction of the average acceleration in each interval? At the beginning of the interval a body is moving to the right along the x-axis at 5 ft/sec,

45. ## physics

A point moving on a straight horizontal line with an initial velocity of 60 fps to the right is given an acceleration of 12 fps2 to the left for 8 sec. Determine (a) the total distance traveled during the 8-sec interval; (b) the displacement during the

46. ## Integration

Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x - ¡ì tan x d sec x = sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì sec^3(x) dx = sec x tan x

47. ## calculus

evaluate the indefinite interval: x sec^(2)(9x) dx i know u=x du=dx dv=sec^(2)(9x) and v = 1/9tan9x....but i don't know where to go from there much help is appreciated

48. ## physics

answer.a car of mass 2000kg,increases its velocity from 10to 40 m\sec in time interval of 2 sec. calclate the force?

49. ## calculus

let f(x) = Sec (x) in the interval 0

50. ## math

Prove the trigonometric identity. tan x+cot x/csc x cos x=sec^2 x __= sec^2x __= sec^2x __ = sec^2x __= sec^2x __ = sec^2x 1/cos^2x=sec^2x sec^2x=sec^2x

51. ## physics help

The magnitude of the velocity of a particle which starts from rest 2 ft below the origin when t = 0 and moves along a vertical axis is directly proportional to the time after starting. The displacement of the particle during the time interval from t = 1

52. ## calculus

When a ball is thrown vertically upward into the air with a velocity of 79 ft/sec its height, y(t), in feet after t seconds is given by y(t) = 79t − 16t 2 . Find the average velocity of the ball over the interval from 3 to 3 + h seconds, h 6=/= 0. 1.

2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents dy/dx when

54. ## physics

car accelerates from 0 to 60 mi/hr in a time of 5.8 secs. a. What is the acceleration of car in m/s squared? need help setting up the problem, thanks acceleration = (speed change)/(time interval) To get the answer in m/s^2, the speed change of 60 mi/hr

55. ## Science

From the below information Speed(m/sec) 2m at 0 sec, 4m at 2 sec, 6m at 3 sec, 8m at 4 sec, 10m at 5 sec. Calculate acceleration. Distance (I am getting answer as 27m but as per book it is 30m. Here as per table velocity is not uniform.) Plz confirm me the

56. ## Calculus

Can someone check my answer? The change in the momentum of an object (Δ p) is given by the force, F, acting on the object multiplied by the time interval that the force was acting: Δ p = F Δt . If the force (in newtons) acting on a particular object is

57. ## Calculus

How do I find the critical values? y= 4/x + tan(πx/8) What I did is I simplified it to y= 4x^-1 + tan(πx/8) then I took the derivative y'= -4x^-2 + (π/8)(sec(πx/8))^2 Then I simplied it y'= -4/x^2 + (π/8)(sec(πx/8))^2 then I found a common denomiator

58. ## Math

1. Find y'(x) when xsecy - 3y sinx = 1 a) (3ycosx - sec y) / (xsec^2y - 3sinx) b) (3cosx - sec x) / (xsecytany - 3sinx) c) (3ycosx - sec y) / (xsecytany - 3sinx) d) (3ycosx - secytany) / xsec^2y - 3sinx) This is what I did: xsecy - 3y sinx = 1 => sec y + x

59. ## Math

Students measure the velocity of a car as it races along a track in a clockwise direction. Their measurements are detailed below: Time (sec) | Velocity (in/sec) 0 | 4 1 | 8 2 | 10 3 | 6 4 | 9 5 | 12 6 | 5 7 | 8 8 | 10 9 | 6 10 | 12 Estimate the distance

60. ## Calculus PLEASE check my work ,

1.) which of the following represents dy/dx when y=e^-2x Sec(3x)? A.3e^-2x sec(3x) tan (3x)-2e^-2x Sec(3x)

61. ## statistics

The time (sec) that it takes a librarian to locate an entry in a file of records on checked-out books has an exponential distribution with lambda symbol=0.5. a)What proportion of all location times are less than 20 sec? At most 20 sec? Atleast 25 sec/

62. ## trigonometry

Find the solutions to the following equation on the interval (-inf, +inf). Round your answer to the nearest ten thousandth. Enter answers in increasing order. 5) sqrt3 sec theta + sec theta cot theta = 0

63. ## calculus

find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x dy/dx = dy/du*du/dx

64. ## Calculus

could anybody please explain how sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ? i just want to know if those two equations are equal, if yes, how did one

65. ## Trig

Find secx if sinx = -4/5 and 270 < x < 360. tan^2x+1=sec^2x (-4/5)^2+1=sec^2x 16/25+1=sec^2x 17/25=sec^2x sqrt 17/5 I don't know if it should be positive or negative.

66. ## Physics

A car accelarates from 40 mph to 60mph in 2.20 sec. determine the car's accelaration in gs. my answer is .911g Determine how far the car went during that 2.20 sec interval. 41.6 m

67. ## chemistry; kinetics

Use the following table to determine the average rate during the period 800 to 1200 seconds for the decomposition of H2O2. 2 H2O2(l) → 2 H2O(l) + O2(g) Time (sec) (H2O2)M 0 2.32 400 1.72 800 1.30 1200 0.98 1600 0.73 a] 1.2 x 10-3M/sec b] 1.6 x 10-3 M/sec

68. ## math

How do I derive the secant reduction rule? Integral (sec x)^n dx = Integral (sec x)^(n-2) * (sec x)^2 dx = Integral ((tan x)^2 + 1)^(n/2-1) * (sec x)^2 dx Doing a substitution with: u = tax x du = (sec x)^2 dx = Integral (u^2 + 1)^(n/2-1) * du At this

69. ## Calculus

Find all the values of (x) in the interval [0, 2Pi], such that sec^2 (x) = 4

70. ## trig

find all soultions of the equation sec^s x-1=0 in the interval{0,2pi}

71. ## Math

The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per second is f (t) = -16t^2 + 80t + 6. According to Rolle's Theorem, what must be the velocity at some time in the interval (2, 3)?

72. ## physics

a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration in first 10 sec.

73. ## physics

a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration in first 10 sec.

74. ## physics

a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration in first 10 sec.

75. ## math;)

What is a simplified form of the expression (sec^3 theta) - (sec theta/cot^2 theta)? a. 0 b. sec theta-tan theta c. cos theta d. sec theta***** Every time I attempt to work out this problem I end up with one. I know the answer is sec theta, but I do not

76. ## acceleration estimate

t(sec) 1 1.5 2 2.5 v(ft/sec) 12.2 1.3 13.4 13.7 velocity of an object moving along a line at various times. How do I estimate the object's acceleration(in ft/sec^2) at t=1 TIA t(sec) 1, 1.5, 2, 2.5 v(ft/sec) 12.2 ,1.3 ,13.4 ,13.7 The second velocity of

77. ## trig

solve the equation 2 sec x- tan x = cot x for the interval 0 to 360

78. ## Trig verifying identities

I am having trouble with this problem. sec^2(pi/2-x)-1= cot ^2x I got : By cofunction identity sec(90 degrees - x) = csc x secx csc-1 = cot^2x Then split sec x and csc-1 into two fractions and multiplied both numerator and denominators by csc and got: sec

79. ## Calculus

For an object whose velocity in ft/sec is given by v(t) = -2t^2 + 4, what is its distance travelled, in feet, on the interval t = 0 to t = 2 secs?

80. ## Pre Calculus

sec x = -2 , π ≤ x ≤ 3π Use a calculator to solve for x in the given interval 9)sinθ=0.1473, 0°≤θ≤90° A) -8.47° B) 8.38° C) 98.47° D) 8.47° 10) cosθ=0.7563,0°≤θ≤90° A) 37.10° B) 49.14° C) -49.14° D) 40.86°

81. ## algebra

i forgot to post these! f(x)=9x+4 and listed in interval notation also: f(x) x2+14x+40 in interval notation and: 1/x^2+81 (interval notation) and: x+11/x^2-121 (interval notation) and: f(x+2) f(x)=6x^2-x+7 You have listed a lot of functions but have said

82. ## calculus trigonometric substitution

∫ dx/ (x^2+9)^2 dx set x = 3tan u dx = 3 sec^2 u du I = 3 sec^2 u du / ( 9 tan^2 u + 9)^2 = 3 sec^2 u du / ( 81 ( tan^2 u + 1)^2 = sec^2 u du / ( 27 ( sec^2 u )^2 = du / ( 27 sec^2 u = 2 cos^2 u du / 54 = ( 1 + cos 2u) du / 54 = ( u + sin 2u / 2) / 54 =

83. ## Science

Predict when a fast toy car can pass a slower toy car . I marked off a distant of 1.5 meters and recorded the time it took the cars to reach the finish line. How do I create a graph and make a prediction? The fast car times were .87 sec. ,.94 sec. ,and .97

84. ## math

Determine all the possible values of x where 0 deg is more than or equal to x and x is more or equal to 360 deg such that i'm not sure the solution, please correct it and how to find the x value, 2 tan x - 1 = cot x solution: (sec x -1)(sec x + 2) = 0 sec

85. ## Physics

During take-off the angular velocity of the blades of a revving engine of engine of an air craft change from 350rev/min to 570rev/min in a time interval of 15minutes. Determine (1).uniform angular acceleration in rad/sec (2).angular displacement during the

86. ## calculus

Use integration by parts to evaluate the integral of x*sec^2(3x). My answer is ([x*tan(3x)]/3)-[ln(sec(3x))/9] but it's incorrect. u=x dv=sec^2(3x)dx du=dx v=(1/3)tan(3x) [xtan(3x)]/3 - integral of(1/3)tan(3x)dx - (1/3)[ln(sec(3x))/3] - [ln(sec(3x))/9]

87. ## Math

Starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. THe distance between the bicycle and the checkpoint is given by the equation d= [105-35t] at

88. ## calc

For an object whose velocity in ft/sec is given by v(t) = −3t2 + 6, what is its distance travelled, in feet, on the interval t = 0 to t = 2 secs?

89. ## calculus

Did I do this problem right? Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x

90. ## Science

Plz help me plot on graph and also the solution. Q. When velocity is 20 m/s time is 0 and velocity 20 m/s time is 5 sec, velocity 10 m/sec time 7 sec, velocity 20 m/sec time 10 sec and velocity 0 time 15 sec. Calculate total distance showing each step and

91. ## calculus

the height in feet of a rocket from ground level is given by the function f(t)= -16t^2+160t. what is the instantaneous velocity of the rocket 3 seconds after it is launched? A 32 feet/sec B 64 feet/sec C 12 feet/sec D 10 feet/sec E 8 feet/sec

92. ## calculus

A flea moves along the line y = -3 according to the equation: x = t^3 - 9t^2 + 24t where x is its x coordinate at time t secs. Determine: 1) the position, velocity, and acceleration of the flea at time 3 secs. Answer: position - 3^3 - 9(3)^2 + 24(3) = 18

93. ## calculus

Me again. One last question! Again, just needed my answer verified with any explanation or walk-through. The position of a particle moving along a coordinate line is s=√(3+6t) with s in meters and t in seconds. find the particle's acceleration at t=1

94. ## physics

a wheel revolves about a fixed horizontal axis through O. During a certain interval of time, the angular velocity (which initially is 20 rad per second clockwise) changes uniformly at such a rate that the angular displacement is 60 rad counterclockwise,

95. ## physics

While doing some interval training, a runner runs a distance interval at a pace of 4.00 m/s. She then runs the next interval at 4.500 m/s and the last interval at 5.500 m/s. Assuming each interval is exactly 125. m, what is her average speed for this

96. ## Physics

In a 1-dimensional problem, a single force acts on a 10 kg object and is given the equation F=ax+b where a=250 N/m, b=25 N, x is position of object. There is a force acting on the object while that object moves from x=0 to x=2 lasting 3 sec. 1) What is the

97. ## math

i need to integrate: (secx)^4 dx let u = sec x dv =sec^3 x dx Start with this. Then, you will have to deal with the integral of sec. You should be able to solve it after a few steps. Looks a little messy.

98. ## physics

if a bird travels 150 cm for 10 sec then 100 cm for 10 sec and then 200 cm for 5 sec. What was the birds average speed?

99. ## Physica

Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec.

100. ## physics

1\ Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec